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2 years ago

2) Triangle ABC is an isosceles triangle with

Mathematics

1 answer:

bulgar [2K]2 years ago

3 0

Answer:

that makes no sense.

Step-by-step explanation:

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Frank received a monthly statement for his college savings account. It listed a deposit of $100 as +100.00. It listed a withdraw

artcher [175]

Answer:

Add: $100

Take Out: $25

Total: $835.50

Step-by-step explanation:

A deposit is an amount that is put into the account, by the owner or by someone else.

A withdrawal is an amount that is taken out of the account.

The overall ending balance shows the total amount in the account at the end of the month.

7 0

2 years ago

2<br> 11 pt<br> 5n +3 = –2(1–7n)

Mkey [24]

Answer:

Step-by-step explanation:

5 0

2 years ago

What is it??????????

spayn [35]

Hey! :)

Some things to note: When you bring a exponent to the numerator, you make it negative.

When you put an exponent to another exponent, you multiply the exponents together.

$(\frac{3x^2y^5}{x^6y^2} )^4\\\frac{81x^8y^{20}}{x^{24}y^8}\\81x^8x^{-24}y^{20}y^{-8}\\\frac{81y^{12}}{x^{16}}$

so that is your answer, please let me know if you need more of an explanation. :)

8 0

2 years ago

Simplify 4√1/32 - 2√1/8

Molodets [167]

Answer would be -0.125 I think I hope so:)

8 0

2 years ago

Read 2 more answers

You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2

defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

$P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715$

Probability a unit is defective and from manufacturer A:

2% of 43%. So

$P(A \cap B) = 0.02*0.43 = 0.0086$

What is the probability that it came from manufacturer A?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015$

0.5015 = 50.15% probability that it came from manufacturer A.

4 0

2 years ago