Answer:
Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.
Step-by-step explanation:
From given scatter plot, we see that upper quartile of Mrs. Cai's class = 4
lower quartile of Mr. Roland’s class = 4
Both are equal so that means.
That means Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.
Hence last choice is correct.
Answer:
Center: (-1,8)
Radius: 1
The graph is attached.
Step-by-step explanation:
The equation of the circle has the form:

Where (h,k) is the point of the center of the circle and r is the radius of the circle.
The equation given in the problem is

Therefore:
h=-1
k=8
Then, the center is (-1,8) and radius is 1.
You can graph the circle with its center at the (-1,8) and a radius of 1 as you can see in the figure attached.
Answer:
44.044%
Step-by-step explanation:
To find the answer we first have to find the value of each percent, to do this we divide 100 by 350, that gets us approximately 0.286. We know that he won 154 of them we then multiply 154 by 0.286 to get the percentage of games he won and we get 44.044.
Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
0.4% of 100 is .4 whoops i thought it was 0.4 as a decimal :P