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kherson [118]
4 years ago
5

Someone help please!!??

Mathematics
1 answer:
krok68 [10]4 years ago
6 0

Answer:

Because you get that 3=68° and 7=68° so 3=7 and that can be only if b and c are parallel

Step-by-step explanation:

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Write the numbers In order from least to greatest,0.44, 3/8,0.5 2/5
Montano1993 [528]
3/8 =0.375
2/5 = 0.4
least to greatest would be
3/8, 2/5, 0.44, 0.5
3 0
4 years ago
Largest 10/13, 11/14, 14/15, 17/18
Katyanochek1 [597]
The answer is 17/18.
You need to make the denominator the same on all the fractions.

Hope this helps.
7 0
4 years ago
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I need helppppp<br><img src="https://tex.z-dn.net/?f=%20-%2029%20%5Cleqslant%20n%20-%2016" id="TexFormula1" title=" - 29 \leqsla
EastWind [94]

Answer: where’s the question?

Step-by-step explanation:

7 0
3 years ago
Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.
Verdich [7]

The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; \rm f(x) = 3x^3 - 13x^2 -3x + 45

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

\rm f(x) = 3x^3 - 13x^2 -3x + 45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

\rm p=\dfrac{All\  the \ positive}{Negative\  factors \ of\  45}

\rm q=\dfrac{All\  the \ positive}{Negative\  factors \ of\  3}

The factor of the term 45 are,

\pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45

And The factor of 3 are,

\pm1, \ \pm3

All the possible roots are,

\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

Now check for all the rational roots which are possible for the given function,

\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}.

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

8 0
2 years ago
What is the length of A in centimeters?
Viktor [21]

Answer: 6

Step-by-step explanation: Look at the other triangle

3 0
3 years ago
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