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elena-14-01-66 [18.8K]
3 years ago
14

How many zeros are there in the standard form of six hundred thousand, twenty?

Mathematics
1 answer:
Julli [10]3 years ago
3 0
There are Three zeros

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WILL MARK BRAINLIEST PLZ HELP
Alik [6]

g(x) = x^3 − x^2 − 4x + 4
g(x) = x^3 + 2x^2 − 25x − 50
g(x) = 2x^3 + 14x^2 − 2x − 14
7 0
3 years ago
1.2 x 10^19 x 5.88 x 10^12
Lapatulllka [165]

9514 1404 393

Answer:

  7.056 × 10^31

Step-by-step explanation:

The applicable rule of exponents is ...

  (10^a)(10^b) = 10^(a+b)

__

  (1.2\times10^{19})\times(5.88\times10^{12})=(1.2\cdot5.88)\times10^{19+12}\\\\=\boxed{7.056\times10^{31}}

As you know, the commutative and associative properties of multiplication let you rearrange the order of the product to any convenient form. Here it is convenient to group the mantissas together and the powers of 10 together.

__

<em>Additional comments</em>

This is a product your scientific or graphing calculator can produce for you. Likely it will display the result in scientific notation because it won't have enough display digits to show you the product any other way. For smaller numbers, you can set the display mode to give you scientific notation.

If you choose to use a spreadsheet to perform this calculation, the numbers would be entered as 1.2e19 and 5.88e12. The result will be something like 7.056e31. You may have to format the display to show 3 decimal places.

7 0
3 years ago
In a shipment of 22 smartphones, 2 are defective. How many ways can a quality control inspector randomly test 4 smartphones, of
Eddi Din [679]

Answer:

Therefore the required ways are =190

Step-by-step explanation:

Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter.

Total number of smartphones =22

Defective phone = 2

Non defective phone = (22-2) =20

The control inspector randomly test 4 smartphones of which 2 are defective.

Non defective phone = 2

The ways to select 2 non defective phone is

^{20}C_2=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!}=\frac{19\times 20}{2} =190

The ways to select 2 defective phone is= ^2C_2=1

Therefore the required ways are = (190×1) =190

5 0
4 years ago
Find the range of the data in the box plot below.
kifflom [539]

Answer:

16

Step-by-step explanation:

22-6=16 ;0

3 0
3 years ago
You have 192 grams of a radioactive kind of iodine. How much will be left
m_a_m_a [10]

Answer:

192/2= 96 g after 7h

96/2=48 g after 14h

48/2= 24 g after 21h

<h2>24/2= 12 g after 28h </h2>
8 0
3 years ago
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