If the geometric series has first term
and common ratio
, then its
-th partial sum is

Multiply both sides by
, then subtract
from
to eliminate all the middle terms and solve for
:



The
-th partial sum for the series of reciprocal terms (denoted by
) can be computed similarly:




We're given that
, and the sum of the first
terms of the series is

and the sum of their reciprocals is

By substitution,

Manipulating the
equation gives

so that substituting again yields

and it follows that

Step-by-step explanation:
f(x) = x³ − 6x² + 9x + 3
Take the derivative and evaluate at x = 2.
f'(x) = 3x² − 12x + 9
f'(2) = -3
Check for local minimums or maximums by setting f'(x) equal to 0.
0 = 3x² − 12x + 9
0 = x² − 4x + 3
0 = (x − 1) (x − 3)
x = 1 or 3
Evaluate f(x) at the critical values, and at the end points.
f(0) = 3
f(1) = 7
f(3) = 3
f(5) = 23
f(x) has a minimum of 3 and a maximum of 23.
Answer:
154
Step-by-step explanation:
11 * 14
= 154
Answer:
Step-by-step explanation:
now the equation looks like
3-4Cos(x)=y
hmmm i'm wondering if you can figure it out from here??? it's the same as the other two.. plug in that
/2 .. can you? :)