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3 years ago

Using an inequality symbol to compare -17——— -1

Mathematics

1 answer:

o-na [289]3 years ago

4 0

Answer:

-17 < -1

Step-by-step explanation:

obviously -1 is greater than -17

< means less than and

> means greater than

therefore we are saying

-17 is less than -1

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I Is x= -2 a solution to: a. 7X = -1 b. X* 14 = -28

raketka [301]

Answer:

Step-by-step explanation:

-2 x 14 = -28

b is the answer

8 0

3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago

What happens if you label the starting number x

tester [92]

You can use any letter but when you label it x you find x

3 0

3 years ago

3.57 x 10 write in standard form

Bess [88]

$\huge\text{Hey there!}$

$\textsf{3.57}\times\textsf{10}^\mathsf{3}\\\\\mathsf{10^3}\\\mathsf{\rightarrow 10\times10\times10}\\\mathsf{\rightarrow100\times10}\\\mathsf{\rightarrow 1,000}\\\\\textsf{3.57}\times\textsf{1,000}\\\rightarrow\textsf{3,570}\\\rightarrow\mathsf{3.57\times10^3}\\\\\huge\boxed{Answer: {\frak{3.57\times 10^3}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

7 0

3 years ago

Kajal holds a ruler in some wavy water. The depth of the water t seconds after she starts measuring it, in cm, is given by D(t)=

Vera_Pavlovna [14]

Answer:

t = 0.77

Step-by-step explanation:

D(t) = 50 - 23 sin(π(t + 0.23))

The value of the sine function has a maximum of -1 and a minimum of 1.

The average value of the sine function is 0.

At maximum sine value:

D(t) = 50 - 23(1) = 50 - 23 = 27

At minimum sine value:

D(t) = 50 - 23(-1) = 50 + 23 = 73

At average sine value of 0:

D(t) = 50 - 23(0) = 50 - 0 = 50

The average depth of the waves is 50 cm.

Now we need to find at what time, t, that occurs.

D(t) = 50 - 23 sin(π(t + 0.23)) = 50

50 - 23 sin(π(t + 0.23)) = 50

-23 sin(π(t + 0.23)) = 0

sin(π(t + 0.23)) = 0

The value of the sine is 0 at 0, π, 2π, ..., nπ

π(t + 0.23) = nπ

t + 0.23 = n

t = n - 0.23

n is all integers, but here we are concerned with the first occurrence after time equals zero, so we want n = 1.

t = 1 - 0.23

t = 0.77

8 0

3 years ago