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NNADVOKAT [17]
3 years ago
7

The volume of a cylinder is 108π cm³ and its height is 12 cm.

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0
The formula for the volume of a cylinder is pi * r^2 * h and it is equal to 108pi. This makes r^2 = 9 which means r=3
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To thase who missed the other ones 4+5-6/7*8-7
hoa [83]

Answer:

-6.67 im pretty sure

Step-by-step explanation:

4+5=9

9-6=3

3/7=0.43

0.43-7=-6.67

the calculator says sum else but like who cares right? lol

4 0
3 years ago
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876,302 to the nearest 10,000
Nataliya [291]

Answer:

Simple answer: 880,302

Step-by-step explanation:

Rule is if the number before the number your rounding is above 4 then it should round up

if its lower than 4 the number your rounding stays as is and the number before it goes down to 0

5 0
3 years ago
The following list shows how many brothers and sisters some students have: 3, 2, 3, 2, 1, 2, 1, 3, 4, 5, 4, 3, 1, 2 State the mo
Wewaii [24]

Answer:

2 and 3

Step-by-step explanation:

8 0
3 years ago
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Agenthammerx Please help me on this I beg you
arlik [135]

Answer:

  • 48°
  • ∠Y ≅ ∠X

Step-by-step explanation:

<h3>Question 1</h3>

<u>Prove that The two triangles are congruent</u>

  • ∠ABD ≅ ∠BDC - given
  • BD ≅ DB - reflexive property
  • ∠ADB ≅ ∠CBD - given
  • ΔABD ≅ ΔCDB - ASA postulate

<u>Find the measure of angle C</u>

  • ∠A ≅ ∠C - Corresponding  parts of congruent triangles
  • m∠C = m∠A = 180° - (62° + 70°) = 180° - 132° = 48°
<h3>Question 2</h3>

<u>Given </u>

  • ΔXYZ with XZ ≅ YZ

Opposite angles are corresponding to the sides.

Therefore the angles opposite to congruent sides are also congruent:

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4 0
3 years ago
The equation, and you have to find what he did wrong. Please help me, i'm stuck- ive been stuck on it since yesterday
bezimeni [28]

9514 1404 393

Answer:

  terms were improperly combined

Step-by-step explanation:

I find the easiest way to identify the error in a solution is to solve it myself and compare with what is shown as being done.

Here, we're starting with ...

  \dfrac{1}{5}g-\dfrac{1}{10}-g+1\dfrac{3}{10}g-\dfrac{1}{10}

If we identify the g-terms and the constant terms, we can group them the way Tyson did:

  \dfrac{1}{5}g+(-1)g+1\dfrac{3}{10}g-\dfrac{1}{10}-\dfrac{1}{10}

The next step is to combine like terms. We can factor out g, so the coefficients are easier to see and combine.

  \left(\dfrac{1}{5}+(-1)+1\dfrac{3}{10}\right)g-\dfrac{1}{10}-\dfrac{1}{10}\qquad\text{step 1a}\\\\\dfrac{1}{2}g-\dfrac{1}{5}\qquad\text{step 2}

The error is 1 3/10 was combined with -2/10 as a constant instead of being combined with -4/5 as a coefficient of g.

3 0
3 years ago
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