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amid [387]
2 years ago
11

a given parabola has an x-intercept at (12,0), and a vertex at (2,-25). What would be the other x-intercept.

Mathematics
1 answer:
Alex17521 [72]2 years ago
5 0
The other x-intercept is located at (-8,0). This is because the vertex is ALWAYS the midpoint between the two x-intercepts. The x coordinate of the vertex is 2. The distance between the vertex and the known x-intercept is 10 units. So go 10 units to the left now, which lands at x = -8
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gizmo_the_mogwai [7]
Wheres the graph top be able to help?
7 0
2 years ago
Answer choices:<br><br> A: y=x<br> B: y=1/4x -2<br> C: y= -x + 7/4<br> D: y= 7/4x -2
Nuetrik [128]

Answer:

b: y=1/4x -2

Step-by-step explanation:

It says the answer in the question. the slope on the graph is really just 1 though.

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2 years ago
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harina [27]

Step-by-step explanation:

The measure of angle y is 62°.

I solve this by

We know: Measures of interior angles in a triangle add up to 180°.

Therefore we have the equation:

60° + 58° + y = 180°

118° + y = 180°         <em>subtract 118° from both sides</em>

118° - 118° + y = 180° - 118°

y = 62°

The measure of angle x is 122°.

I solve this by

Angles 58° and x are supplementary angles.

Supplementary angles add up to 180°.

Therefore we have the equation:

x + 58° = 180°            <em>subtract 58° from both sides</em>

x + 58° - 58° = 180° - 58°

x = 122°

8 0
2 years ago
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Murljashka [212]

Answer:

1. 5x+3y, 2. 5h, 3. 5x+20-2x+8 --> 3x+28, 4. 2y-6+5x+5 --> 2y+5x-1

Step-by-step explanation:

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3 years ago
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qwelly [4]
It's the third graph, the one where the absolute function is opening downwards
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