Answer: Yes
Explanation:
Public key encryption is the encryption technique that is used for private keys and public keys for securing the system.Public key is used for encryption and private key is for decryption.Public keys can only open content of the system
- According to the question, public key encryption is secure for coffee shop customer payment process as they are stored on digital certificates in long form for verifying digital signature and encrypting information.Its computation is difficult to crack through power computer access.
- Other options is incorrect as encryption is not a problem for payment procedures. Thus, the correct option is yes ,public key encryption is secure method for coffee shop customers .
Answer:
- var projected_fee = 6000;
-
- for(var i = 1; i <= 5; i++){
- projected_fee = projected_fee * 0.02 + projected_fee;
- console.log("$" + projected_fee.toFixed(2));
- }
Explanation:
Firstly, create a variable, projected_fee, and set the initial tuition fee value to it (Line 1).
Next, user a for loop that run for 5 times to repeatedly calculate the projected_fee based on 2 percent of increment rate (Line 4) and display the projected fee to console terminal (Line 5). The output should be
$6120.00
$6242.40
$6367.25
$6494.59
$6624.48
You add all the addresses into excel and and do mail-merge with the invitation. Adding the 100 addresses is probably a lengthy process but once this is complete you can just add on addresses and once a year or whenever you have to mail something to everyone, it's a only mouse-click.
Answer:
cooperate society
Explanation:
A cooperative society is a voluntary association that started with the aim of the service of its members.
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
