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Lerok [7]
3 years ago
15

Can you right the C++ of this algorithm? Inizio = Start, Fine= End. THANK YOU SO MUCH!!

Computers and Technology
1 answer:
posledela3 years ago
4 0
<span>#include <iostream> using namespace std; bool bears(int n); int main(){ int number; do{ cout<<"enter the amount of bears (press 0 to stop the program): "; cin>>number; if (bears(number)){ cout<<"you have reached the goal!"<<endl; } else{ cout<<"sorry, you have not reached the goal."<<endl; } }while(number != 0); } bool bears(int n){ if (n < 42){ return false; } else if (n == 42){ return true; } else{ if (n % 5 == 0){ return bears(n - 42); } else if(n % 2 == 0){ return bears(n / 2); } else if(n % 4 == 0|| n % 3 == 0) { int one; int two; one=n%10; two=(n%100)/10; return bears(n - one * two); } } <span>}</span></span>
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Is recursion ever required to solve a problem? What other approach can you use to solve a problem that is repetitive in nature?
Setler79 [48]

Answer:

No you can not tell that recursion is ever required to solve a problem.

Recursion is required when in the problem, the solution of the input depends on the solution of the subsets of the input.

Iteration is also another form of repetitive approach we follow to solve that kind of problems.

But the difference between recursion and iteration is :

  • In recursion we call the function repeatedly to return the result to next level.
  • In iteration certain bunch of instructions in a loop are executed until certain conditions met.

Explanation:

For example in the Fibonacci sequence problem, to find f_{n}, we need to compute f_{n-1} and f_{n-2} before that.

  • In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.

                           Fibonacci(n)

                           1. if(n==0 or n==1)

                           2.       return 1.

                           3.else

                           4.      return( Fibonacci(n-1)+Fibonacci(n-1) )

  • But in case of iteration we run a loop for i=2 to n, within which we add the value of current f_{i-1} and f_{i-2} to find the value of f_{i}

                           Fibonacci(n)

                           1. if(n<=2)

                           2.    result = 1

                           3.     else

                           4. result1 =1 and result2=1.

                           5.      {  result = result1 +result2.

                           6.         result1= result2.

                           7.         result2 = result.

                           8.      }

                           9.  output result.

8 0
3 years ago
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