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Hitman42 [59]
4 years ago
10

I think it’s 16, can anyone confirm this?

Mathematics
2 answers:
zhannawk [14.2K]4 years ago
8 0

Answer:

So we can do 3*2/2 which is equal to 3. Thats area of the triangle. Then we multiply by 4 for all sides of a pyramid. 3*4 = 12. Lateral area means all sides of the figure not top and bottom, but we know that there is not a top, but there is a bottom. 12 is answer for lateral area

<h2><u>Answer is 12 not 16</u></h2>

Marianna [84]4 years ago
4 0

Answer:

Step-by-step explanation:

I believe it is actually 12 in^2

First you have to find the perimeter it is easy to just multiply the sidelength x  4 because it is square.

next you have to multiply the perimeter with the slant height

then you divide your answer by 2

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Last week, Ann bought 9 books and 5 movies for a total of $124.
Elodia [21]

Answer:

$6

Step-by-step explanation:

Set up a system of equations where b is the cost of a book and m is the cost of a movie:

9b + 5m = 124

4b + 21m = 318

Solve by elimination by multiplying the top equation by -21 and the bottom equation by 5:

-189b - 105m = -2604

20b + 105m = 1590

Add the equations together, then solve for b:

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So, the cost of a book is $6

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SCORPION-xisa [38]

Value of the expression will be 7

<u><em>Explanation</em></u>

Given value of the variables are : p= \frac{1}{2} and q=7

Given expression: 8p+3q-18

So, <u>plugging the values</u> of p and q into the above expression, we will get...

8p+3q-18\\ \\ = 8(\frac{1}{2})+3(7)-18\\ \\ =4 + 21-18\\ \\ =25-18\\ \\ =7

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Answer: 600

<u>Step-by-step explanation:</u>

   20    x    30

= 2 x 10 x   3 x 10

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An open top rectangular box with a square bottom has a volume of 120 cubic meters. Its bottom and sides are made from two differ
denpristay [2]

Answer:

The dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

Step-by-step explanation:

Let's define some notation first:

h = represent the height of the box

a= length of a side on the bottom

We need to remember that we have on this case an open box, so then we don't have a top part.

Let's begin with the formula for the volume of the box, we have a total volume given of 120m^3, and we know that the volume for a box is the product of the area and the height like this:

120 m^3 = a^2 h   (1)

From equation (1) we cna solve for the height and we got:

h=\frac{120}{a^2}   (2)

Now let's move to th surface area formula. The top bottom area is a^2 and the surface area for the four lateral sides is 4ah. Since we know that the cost for the bottom material is 10 $ per each square meter and for the sides is 12$ per square meter we can create a function cost like this:

Cost= Cost of  bottom+ Cost of sides

Cost = 10a^2 + (12)(4ah) = 10a^2 + 48ah   (3)

Now we can substitute into equation (3) the equation (2) like this:

Cost = 10a^2 + (12)(4ah) = 10a^2 + 48a\frac{120}{a^2}=10a^2 +\frac{5760}{a}   (4)

Now in order to find the minimum cost, we can take the first derivate for the expression (4) like this

\frac{d}{da} Cost = 20a -\frac{5760}{a^2}

We can set this equal to 0 and solve for a and we got:

\frac{5760}{a^2}= 20a

\frac{5760}{20}=a^3

a=6.604

And since we have a we can find h using the expression (2) like this:

h=\frac{120}{a^2}=\frac{120}{6.604^2}=2.752  

So then the dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

6 0
3 years ago
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