Answer:
![x = 5](https://tex.z-dn.net/?f=x%20%3D%205)
Step-by-step explanation:
Given
![\sqrt x + \sqrt x = (4.4,4.5)](https://tex.z-dn.net/?f=%5Csqrt%20x%20%2B%20%5Csqrt%20x%20%3D%20%284.4%2C4.5%29)
Required
Find x
When the result is 4.4, we have:
![\sqrt x + \sqrt x = 4.4](https://tex.z-dn.net/?f=%5Csqrt%20x%20%2B%20%5Csqrt%20x%20%3D%204.4)
This gives:
![2\sqrt x = 4.4](https://tex.z-dn.net/?f=2%5Csqrt%20x%20%3D%204.4)
Divide both sides by 2
![\sqrt x = 2.2](https://tex.z-dn.net/?f=%5Csqrt%20x%20%3D%202.2)
Square both sides
![x = 2.2^2](https://tex.z-dn.net/?f=x%20%3D%202.2%5E2)
![x = 4.84](https://tex.z-dn.net/?f=x%20%3D%204.84)
When the result is 4.5, we have:
![\sqrt x + \sqrt x = 4.5](https://tex.z-dn.net/?f=%5Csqrt%20x%20%2B%20%5Csqrt%20x%20%3D%204.5)
![2\sqrt x = 4.5\\](https://tex.z-dn.net/?f=2%5Csqrt%20x%20%3D%204.5%5C%5C)
Divide both sides by 2
![\sqrt x = 2.25](https://tex.z-dn.net/?f=%5Csqrt%20x%20%3D%202.25)
Square both sides
![x = 2.25^2](https://tex.z-dn.net/?f=x%20%3D%202.25%5E2)
![x = 5.0625](https://tex.z-dn.net/?f=x%20%3D%205.0625)
So, the value of x is between 4.84 and 5.0625
i.e.
![x = (4.84,5.0625)](https://tex.z-dn.net/?f=x%20%3D%20%284.84%2C5.0625%29)
The only integer between the above interval is 5.
Hence:
![x = 5](https://tex.z-dn.net/?f=x%20%3D%205)
We don't consider 0 a common multiple. So I don't think it is.
Answer:
1/3x=y-3, y=2/3x
Step-by-step explanation:
1/3x=y-3 is a linear function because there are no powers.
y=x^3+2 is not a linear function because x is squared by 3.
y=6x^2 is not a linear function because x is squared by 2.
y=2/3x is a linear function because there are no powers.
If this helps please mark as brainliest