"how do we store information in long term memory?"
1 answer:
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Answer:
Check the explanation
Explanation:
Each Bagel-type small monster has 0.35 probability of being a Sesame Seed-subtype and 0.2 probability of being a Whole Wheat-subtype.
The probability that exactly 8 of them are Whole Wheat-subtype is using multiplication principle, because first need to choose which 8 are Whole Wheat-subtype, and if exactly 8 of them are Whole Wheat-subtype, then other two are not Whole Wheat-subtype. The former has probability 0.2, while the latter has probability 1-0.2 = 0.8 .
Kindly check the attached images below for the complete answer to the question above
Answer:
Condition one - 1 time
Condition two - 2 times
Explanation:
Given
The above code segment
Required
Determine the number of times each print statement is executed
For condition one:
The if condition required to print the statement is: <em>if (arr[row][col] >= arr[row][col - 1]) </em>
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For the given data array, this condition is true only once, when
and
i.e.
<em>if(arr[row][col] >= arr[row][col - 1]) </em>
=> <em>arr[1][2] >= arr[1][2 - 1]</em>
=> <em>arr[1][2] >= arr[1][1]</em>
<em>=> 5 >= 3 ---- True</em>
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The statement is false for other elements of the array
Hence, Condition one is printed once
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For condition two:
The if condition required to print the statement is: <em>if (arr[row][col] % 2 == 0) </em>
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The condition checks if the array element is divisible by 2.
For the given data array, this condition is true only two times, when
and
and
i.e.
<em>if (arr[row][col] % 2 == 0) </em>
<em>When </em> and
<em>=>arr[0][1] % 2 == 0</em>
<em>=>2 % 2 == 0 --- True</em>
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<em>When </em> and
<em>=>arr[1][0] % 2 == 0</em>
<em>=> 4 % 2 == 0 --- True</em>
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The statement is false for other elements of the array
Hence, Condition two is printed twice