Answer:
B but don't be surprised if it is not the answer given. It's just the best of a bunch of poor choices.
Explanation:
This is actually not an easy question to answer. It's one of those answers that has elements of "Some do and Some don't" in them.
A: is not true for painters and it is not necessarily true for C for painters.
D: photographer can pose his subjects. A painter can pose someone, but not always.
C: Answered under A.
I think the answer you are forced to choose is B, but neither one has to do it. Still life painters ( a bowl of fruit, a bouquet of flowers) and photographs pose the subjects carefully and do not want the fruit or flowers to move around.
I'd pick B, but it does not have to be the answer. I just think it is less wrong than the others.
Something like this?
h1 = int(input())
m1 = int(input())
s1 = int(input())
h2 = int(input())
m2 = int(input())
s2 = int(input())
s = h2*3600 + m2*60 + s2 - (h1*3600 + m1*60 + s1)
print(s)
Answer:
boolean isEven = false;
if (x.length % 2 == 0)
isEven = true;
Comparable currentMax;
int currentMaxIndex;
for (int i = x.length - 1; i >= 1; i--)
{
currentMax = x[i];
currentMaxIndex = i;
for (int j = i - 1; j >= 0; j--)
{
if (((Comparable)currentMax).compareTo(x[j]) < 0)
{
currentMax = x[j];
currentMaxIndex = j;
}
}
x[currentMaxIndex] = x[i];
x[i] = currentMax;
}
Comparable a = null;
Comparable b = null;
if (isEven == true)
{
a = x[x.length/2];
b = x[(x.length/2) - 1];
if ((a).compareTo(b) > 0)
m = a;
else
m = b;
}
else
m = x[x.length/2];
