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Nataly [62]
2 years ago
10

A(n ____ enables a database administrator to define schema components.

Computers and Technology
1 answer:
zzz [600]2 years ago
8 0
Ig a(n) network cuz the database management language uses a schema and subschema data definition language; the schema data definition language enables database administrators to define schema components, and the subschema data definition language allows the application programs to define database components that will be used.

hope this helps u out. :)
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sammy [17]

Answer:

True

Explanation:

hoped I helped Im Eve btw Have a great day and consider marking this brainliest if you do thank you in advanced!

6 0
3 years ago
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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Which of these is a physical health benefit provided by playing team sports? A. a spiritual connection to others B. lower choles
AfilCa [17]

Answer:

B. lowering cholesterol

Explanation:

Edge 2021, made a 100 on the quiz. Good luck :)

3 0
2 years ago
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What do we call exceptions to the exclusive rights of copyright law?
Studentka2010 [4]

Answer:

Fair use

Explanation:

I don't know if this is correct but Its the best option.

4 0
3 years ago
In python, what is the difference between a dictionary and a set? How are they similar?
yuradex [85]

Answer:

"A set is an unordered collection. A dictionary is an unordered collection of data that stores data in key-value pairs."

Explanation:

Set =>

Collection of non-repetitive elements.

Unordered

Unindexed

No way to change items.

Dictionary =>

Collection of key-value pairs.

Unordered

Indexed

Mutable

4 0
2 years ago
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