1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
a_sh-v [17]
4 years ago
5

This​ year, druehl,​ inc., will produce 57 comma 60057,600 hot water heaters at its plant in​ delaware, in order to meet expecte

d global demand. to accomplish​ this, each laborer at the plant will work 200200 hours per month. if the labor productivity at the plant is 0.250.25 hot water heaters per labor​ hour, how many laborers are employed at the​ plant?
Mathematics
1 answer:
ivolga24 [154]4 years ago
5 0
If one labour works 200 hours per month, the amount of hot water heaters the labour can produce is = 200 × 0.25 = 50 hot water heaters

The demand is to produce 57600 hot water heaters

The number of labourers employed is 57600 ÷ 50 = 1152 labourers
You might be interested in
Your friend has a recipe book with 1000 recipes.she makes 2 new recipes each week. after 1 year, what fraction of the recipes ha
adoni [48]

After one year, the fraction of the recipe that she has not made is 896/1000 or 112/125

Fraction:

A fraction means the part of the whole thing.

For example, a pizza is divided into four equal pieces, then each piece is represented by ¼.

Given:

Your friend has a recipe book with 1000 recipes.

She makes 2 new recipes each week.

We need to find the fraction of the recipes has she not made after one year.

We know that,

1 year = 52 week

So, here they given that she will make 2 recipes per week.

So, in one year she will make

=> 2 x 52 = 104

So, the remaining recipes in the book is

=> 1000 - 104

=> 896

So, the fraction is

=> 896 / 1000

When we simplify it, then we get

To simplify, we need to find the Greatest Common Factor (GCF) of 896 and 1000, if it exists, and reduce our fraction by dividing both numerator and denominator by it. GCF = 8, and getting our simplified answer:

=> 112 / 125

To know more about Fraction here

brainly.com/question/10354322

#SPJ4

7 0
2 years ago
Find the sum of the series: .25+.125+.0625+....
alexgriva [62]
Hope it will help you!

4 0
4 years ago
To the nearest tenth, what is the area of a circle whose diameter is 9 feet? Use 3.14 for π . Enter your answer in the box.
Rus_ich [418]
A=3.14*4.5^2=63.585=63.6
8 0
3 years ago
Read 2 more answers
18.25=4(1.5-3.75x)-.25(4x-5) wat is x?
sdas [7]
The answer is x= - 11/ 16
You can check this by plugging in x for -11/16



5 0
3 years ago
Cos (B+C - A) + cos (C+ A-B) + cos( A+B+C)<br>= 1 + 4 cos A.cos B.cos C.​
Stels [109]
Can you explain more
8 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP I HAVE 21 POINTS PLEASE Part A: The sun produces 3.9 ⋅ 10^33 ergs of radiant energy per second. How many ergs of rad
    10·2 answers
  • Keshav write the multiples of 7 on his paper, but his sister accidentally erased some of them. Determine what multiple is missin
    5·1 answer
  • A bag contains four chips of different​ colors, including​ red, blue,​ green, and yellow. A chip is selected at random from the
    13·1 answer
  • X is 6 more than twice y.
    14·2 answers
  • How do you solve -x=1/x
    7·1 answer
  • Use the rule y = 6x to fill in the table with the missing number.
    6·2 answers
  • 1) If a card is drawn from a pack of 52 cards of which 26 are black (13 spades A, 2, 3,…, 10, J, Q, K); 13 are clovers); and 26
    6·2 answers
  • Solve the equation. <br><img src="https://tex.z-dn.net/?f=%20%7Cx%20-%20%20%5Cfrac%7B4%7D%7B3%7D%20%7C%20%20%3D%20%20%7Cx%20%2B%
    15·2 answers
  • Calvin has a gift card which he is using to buy candy (x), and he has been tracking how much money (y) he spends. He noted that
    8·1 answer
  • Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case. ( pls answer fast )
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!