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schepotkina [342]
2 years ago
10

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case. ( pls answer fast )

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
8 0

Answer:

95

Step-by-step explanation:

The smallest number that divided by 6, 15, and 18 leavses 5 in each case is 95

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please help i will mark brainliest, no spam answers i will report.
vovikov84 [41]

9514 1404 393

Answer:

  (c)  (3, 3)

Step-by-step explanation:

Point E partitions both the x-distance and the y-distance in the ratio 2 : 1. That is, for either the x-coordinates or the y-coordinates, ...

  CE : ED = 2 : 1

Try the answers with the x-coordinates.

  CE : ED = (1 -(-1)) : (5 - 1) = 2 : 4 . . . . incorrect

  CE : ED = (-3 -(-1)) : (5 -(-3)) = -2 : 8 . . . . incorrect

  CE : ED = (3 -(-1)) : (5 -3) = 4 : 2 = 2 : 1 . . . . correct

  CE : ED = (-1 -(-1)) : (5 -(-1)) = 0 : 6 . . . . incorrect

The only viable choice is (3, 3).

_____

<em>Alternate solution</em>

For a partitioning of m : n, the desired point is ...

  E = (n×C +m×D)/(m+n)

For partitioning of 2 : 1, the desired point is ...

  E = (1×(-1, -3) + 2×(5, 6))/(2+1) = (-1+10, -3 +12)/3

  E = (3, 3)

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Answer:

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Step-by-step explanation:

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