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irinina [24]
3 years ago
7

The arrow next to All Programs indicates _____. that this item cannot be selected that this was the most recently used item the

importance of the item the presence of a submenu
Computers and Technology
2 answers:
stich3 [128]3 years ago
3 0
The presence of a submenu is the answer.
gtnhenbr [62]3 years ago
3 0

Answer:

D.

Explanation:

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A network administrator enters the command ipv6 router ospf 110 in global configuration mode. What is the result of this command
Zepler [3.9K]

Answer:

The OSPFv3 AS number will be assigned an ID of 110

Explanation:

If we don't have ipv4 addressing previously, we are going to assign the router-id manually.

We are going to receive a message about the assignation manually.

We can assign a router-id with the next line:

#router-id 1.1.1.1

If we already have the ipv4 addressing, the router going to assign the router-id automatically.

4 0
4 years ago
. In the BorderLayout class, what are NORTH, SOUTH, EAST, WEST, and CENTER?
ycow [4]

Answer:

A BorderLayout corresponds to a layout type where the components are organized along geographical directions represented by NORTH, SOUTH, EAST, WEST, and CENTER.

Explanation:

The layout class is awt determines the actual placement of components in the user interface. BorderLayout is a layout where the components are organized along geographical directions represented by NORTH, SOUTH, EAST, WEST, and CENTER. For example:

Panel p = new Panel();

p.setLayout(new BorderLayout());

p.add(new TextArea(), BorderLayout.CENTER);

p.add(new Button("Close"), BorderLayout.SOUTH);

This code segment will add a textarea at the CENTER of the interface and a button 'Close' towards the SOUTH.

8 0
3 years ago
Which of the following statements are true concerning abstraction and refinement? Select 3 options:
Akimi4 [234]

Answer:

The answer to this question is given below in the explanation section

Explanation:

First,  we need to know what is abstraction and refinement.

Abstraction and refinement are used in application/system development in the field of computing. Abstraction is used to abstract the details from the model. It means that displaying only essential information about the the model and hiding other details. While refinement is the idea that is used in software development by moving through each level of abstraction and incrementally refining each level of abstraction, providing more detail at each increment. Refinement is the inverse of abstraction.  

So the correct options to this question are:

  • Models may be abstracted and refined depending on the goals of the project.
  • Abstraction is a technique used in computational thinking.
  • Refinement is the inverse of abstraction.

5 0
3 years ago
How do you print a document?
Anton [14]
Press ctrl +p and select the printer name then press print
5 0
3 years ago
Read 2 more answers
(In Java) An n X n matrix is called a positive Markov matrix if each element is positive and the sum of the elements in each col
Stells [14]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 System.out.print("Enter a 3 x 3 matrix: ");

 double[][] myArr = new double[3][3];

 for(int i =0;i<3;i++){

        for(int j = 0;j<3;j++){

         myArr[i][j] = input.nextDouble();}}

 boolean isMarkov = true;

 double colsum = 0.00;

 for(int i =0;i<3;i++){

     for(int j = 0;j<3;j++){

         colsum += myArr[j][i];}

     if(colsum != 1.00){

         isMarkov = false;

         break;}

     colsum = 0.00;

 }

 if(isMarkov){    System.out.print("It is a Markov matrix"); }

 else{  System.out.print("It is a not Markov matrix"); }

}

}

Explanation:

This line prompts the user for a 3\ x\ 3 matrix

 System.out.print("Enter a 3\ x\ 3 matrix: ");

This declares a 3 x 3 matrix

 double[][] myArr = new double[3][3];

The following iteration gets input for the 3\ x\ 3 matrix

<em>  for(int i =0;i<3;i++){</em>

<em>         for(int j = 0;j<3;j++){</em>

<em>          myArr[i][j] = input.nextDouble();}}</em>

This declares and initializes a boolean variable to true

 boolean isMarkov = true;

This declares and initializes colsum to 0 i.e. the sum of each column

 double colsum = 0.00;

The following iteration sums up each column

<em>  for(int i =0;i<3;i++){</em>

<em>      for(int j = 0;j<3;j++){</em>

<em>          colsum += myArr[j][i];}</em>

This checks if the column sum is not 1

     if(colsum != 1.00){

If true that the column sum is not 1, the boolean variable is updated to false

         isMarkov = false;

And the loop is terminated

        break;}

     colsum = 0.00;

 }

If isMarkov is true, the system prints that it is a Markov matrix

 if(isMarkov){    System.out.print("It is a Markov matrix"); }

If isMarkov is false, the system prints that it is not a Markov matrix

 else{  System.out.print("It is a not Markov matrix"); }

5 0
3 years ago
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