Answer:
There could be an issue with your SIM card, or the problem could be on your carrier's end. Possible causes of the 'not registered on network' error include:
Your phone's firmware or operating system is out of date.
The SIM card is disconnected or damaged.
Your carrier is not selected in your phone's settings.
Your carrier is experiencing an outage.
Explanation:
Answer:
A for loop can be used to make something repeat as many times as you program it to, but a while loop only stops when you complete the task, or a certain condition is met. So, if you program a for loop to fill a bucket six times it will fill the bucket six times.
The question given is incomplete and by finding it on internet i found the complete question as follows:
Direct Mapped Cache.
Memory is byte addressable
Fill in the missing fields based upon the properties of a direct-mapped cache. Click on "Select" to access the list of possible answers Main Memory Size Cache Size Block Size Number of Tag Bits 3 1) 16 KiB 128 KiB 256 B 20 2) 32 GiB 32 KiB 1 KiB 3) 64 MiB 512 KiB 1 KiB Select] 4 KiB 4) 16 GiB 10 Select ] Select ] 5) 10 64 MiB [ Select ] 6) Select] 512 KiB 7
For convenience, the table form of the question is attached in the image below.
Answers of blanks:
1. 3 bits
2. 20 bits
3. 64 MB
4. 16 MB
5. 64 KB
6. 64 MB
Explanation:
Following is the solution for question step-by-step:
<u>Part 1:</u>
No. of Tag bits = No. of bits to represent
Tag bits = Main memory - cache size bits -------- (A)
Given:
Main memory = 128 KB = 
Cache Memory = 16 KB = 
Putting values in A:
Tag bits = 17 - 14 = 3 bits
<u>Part 2:</u>
Tag bits = Main memory - cache size bits -------- (A)
Given:
Main memory = 32 GB = 
Cache Memory = 16 KB = 
Putting values in A:
Tag bits = 35 - 15 = 20 bits
<u>Part 3:</u>
Given:
Tag bits = 7
Cache Memory = 512 KB = 
So from equation A
7 = Main Memory size - 19
Main Memory = 7 + 19
Main memory = 26
OR
Main Memory = 
<u>Part 4:</u>
Given that:
Main Memory Size = 
Tag bits = 10
Cache Memory Bits = 34 - 10 = 24
Cache Memory Size = 
<u>Part 5:</u>
Given that:
Main Memory Size = 64 MB = 
Tag bits = 10
Cache Memory Bits = 26 - 10 = 16
Cache Memory Size = 
<u>Part 6:</u>
Cache Memory = 512 KB = 
Tag Bits = 7
Main Memory Bits = 19 + 7 = 26
Main Memory size = 
i hope it will help you!
Technologies that can operate in the 125 kHz to 134 kHz range is the
B. RFID
Explanation:
- RFID is technology which works on radio frequency and it is used for the auto-identification for the different object.
- The RFID system mainly consists of two parts. In this RFID system, this RFID reader continuously sends radio waves of a particular frequency
- RFID is the use of radio waves to read and capture information stored on a tag attached to an object, providing a unique identifier for an object.
- Active RFID tags have a transmitter and their own power source. Instead, they draw power from the reader, which sends out electromagnetic waves that induce a current in the tag's antenna.
- Semi-passive tags use a battery to run the chip's circuitry, but communicate by drawing power from the reader.
- Radio frequency identification (RFID) can operate in three frequency bands: 125 kHz to 134 kHz, 13.56 MHz, or 856 MHz to 960 MHz. Bluetooth is 2.4 GHz; NFC is 13.56 MHz; and LTE is between 600 MHz and 6 GHz.
The answer would be computer