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3 years ago

4x = 3x+5 This is hard!

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

6 0

Answer:

x=5

Step-by-step explanation:

4x-3x=5

x=5

qwelly [4]3 years ago

6 0

Answer: x=5

Let’s start by rewriting the equation

4x=3x+5

Let’s combine like terms- 4x and 3x. We’ll do this by subtracting 3x on both sides.

x=5

This is your answer! Hope this helps comment below for more questions :)

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The value of (1-w) (1 -w^2), where w is the cube root of a complex number is

NeX [460]

Answer:(1-w) (1-w*2)

=1-w*2-w+w*3

=1-w-w*2+1

=1-1+1

Step-by-step explanation:

at first we should multiply them with each other

then, put the value of w*3 i.e. w*3=1

then, put the value of -w-w*2 i.e. 1

then, the final answer is 1.

3 0

3 years ago

an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.

dolphi86 [110]

Answer:

$\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}$

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

$A_\triangle=\dfrac{bh}{2}$

b - base

h - height

We need a length of a height.

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have:

$leg=5,\ leg=h,\ hypotenuse=20$

Substitute:

$5^2+h^2=20^2$

$25+h^2=400$ subtract 25 from both sides

$h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm$

Calculate the area:

$A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2$

8 0

4 years ago

In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate

oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = $\pi$ ×14 = 44 cm

length of arc ab = half of circumference of bigger circle = $\pi$ ×28 = $\frac{22}{7}$ ×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

= $\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}$

= $\frac{\pi }{2} (28^{2} -14^{2} )$

solving we gen area of shaded region = 924

7 0

3 years ago

Plz help me!!

zmey [24]

Y> -4a=36 or 36=-4a< y

3 0

3 years ago

Kiera is in her last year of college at the University of Houston. She has a scholarship that pays 75% of her costs. Her classes

sergiy2304 [10]

If the scholarship pays 75% of her classes cost, that means that she has to pay the 25% remaining of the classes cost so if we calculate it as follow:

0.25 * $14,000 = $3,500
=================================================================
Another method to understand:
if the scolarship pays 75% of her classes that will be
0.75* $14,000 = $10,500

now she has to pay the remaining of the total cost and that will be
$14,000 - $10,500 = $3,500.

5 0

4 years ago