All categories

3 years ago

4(w+4)+6(4+2w) i’m just really confused and these are test corrections

Mathematics

2 answers:

Brut [27]3 years ago

6 0

Answer:

16w+40

Step-by-step explanation:

UNO [17]3 years ago

4 0

Answer:

16w+40

Step-by-step explanation:

To simplify this equation you have to use the distributive property first. This means you multiply 4 by everything in the first set of parentheses and you multiply 6 by everything in the second set of parentheses. This leaves you with 4w+16+24+12w.

Next, you combine like terms by adding 4w and 12w to get 16w, and 16 and 24 to get 40.

So, your final answer is 16w+40.

You might be interested in

Identify the equations as parallel lines, perpendicular lines, or neither.

Sever21 [200]

Answer:

Perpendicular

Step-by-step explanation:

A perpendicular line has an opposite slope. one of these has 5x and one has -5x, these are opposite, so they are perpendicular.

6 0

3 years ago

What is the angle measure of angle ABC?

Aliun [14]

Answer:

92°

Step-by-step explanation:

First, find the value of x.

3x + 23 = 4x (corresponding angles are congruent)

Subtract 3x from each side

23 = 4x - 3x

23 = x

x = 23

Angle ABC = 4x

Plug in the value of x

Angle ABC = 4(23)

Angle ABC = 92°

6 0

3 years ago

Wendy tasted 12 desserts from each bakery in her county. Each bakery has an equal number of desserts.

Radda [10]

Answer:

thanks for the points but gl on the work

Step-by-step explanation:

8 0

3 years ago

The sum of the first 15 terms of an arithmetic series

ale4655 [162]

Answer:

d=4

Step-by-step explanation:

SUM OF 15 terms = 615

T5 = 53

T5 = a+(n-1)d

53 = a + 4d

4d = 53 - a

d = (53-a)/4

S15 = 15/2 (2a+14d) =615

15/2 [2a + 14×(53-a)/4 ]

=15/2 [ 2a +(53×14 - 14a )/4 ]

=15/2 [ (8a +742 - 14a ) /4]

615×8 = 15(-6a +742)

-6a+72=615×8/15 =41

-6a+72=42

-6a = - 72 + 42 = -30

a = 30/6= 5

a = 5

T5 = 5 + 4×d = 53

4d= 53 - 5 = 48

4d=48

d=4

Common difference is 4

7 0

2 years ago

A) Consider the weighted voting system (q: 8,4,2,1). Find the Banzhaf power distribution of this weighted voting systwm when q=1

wel

Answer:

(q: 8,4,2,1)

q = 12

List all coalitions ( 2 pair)

$(P_1,P_2)=\text{Total weight }=8+4=12 \\(P_1,P_3)\text{Total weight }=8+2=10 \\(P_1,P_4)\text{Total weight }=8+1=9 \\(P_2,P_3)\text{Total weight }=4+2=6 \\(P_2,P_4)\text{Total weight }=4+1=5 \\(P_3,P_4)\text{Total weight }=2+1 = 3$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

So, $(P_1,P_2)=\text{Total weight }=8+4=12$ will go further in winning coalition

Coalitions ( 3 pair or more)

$(P_1,P_2,P_3)=\text{Total weight }=8+4+2=14 \\(P_1,P_2,P_4)\text{Total weight }=8+4+1=13 \\(P_1,P_3,P_4)\text{Total weight }=8+2+1=11 \\(P_2,P_3,P_4)\text{Total weight }=4+2+1=7 \\(P_1,P_2,P_3,P_4)\text{Total weight }=8+4+2+1=15$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

$(P_1,P_2,P_3)=\text{Total weight }=8+4+2=14$

$(P_1,P_2,P_4)\text{Total weight }=8+4+1=13$

$(P_1,P_2,P_3,P_4)\text{Total weight }=8+4+2+1=15$

winning coalitions:

$(P_1,P_2)$

$(P_1,P_2,P_3)$

$(P_1,P_2,P_4)$

$(P_1,P_2,P_3,P_4)$

In case of $(P_1,P_2)$

If Player 1 leaves

So, total weight will be 4

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8

So, Player 2 is critical

In case of $(P_1,P_2,P_3)$

If Player 1 leaves

So, total weight will be 4+2=6

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+2=10

So, Player 2 is critical

If Player 3 leaves

So, total weight will be 8+4=12

So, Player 3 is not critical since total weight is equal to q

In case of $(P_1,P_2,P_4)$

If Player 1 leaves

So, total weight will be 4+1=5

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+1=9

So, Player 2 is critical

If Player 4 leaves

So, total weight will be 8+4=12

So, Player 4 is not critical since total weight is equal to q

$(P_1,P_2,P_3,P_4)$

If Player 1 leaves

So, total weight will be 4+2+1=7

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+2+1=11

So, Player 2 is critical

If Player 3 leaves

So, total weight will be 8+4+1=13

So, Player 3 is not critical since total weight is greater than q

If Player 4 leaves

So, total weight will be 8+4+2=14

So, Player 4 is not critical since total weight is greater than q

Player Times critical Banzhaf power index

1 4 $\frac{4}{8} \times 100 = 50\%$

2 4 $\frac{4}{8} \times 100 = 50\%$

3 0 0

4 0 0

Sum = 8

3 0

3 years ago