roster[50] is an array of "students", so roster[9] is a "student". Therefore, roster[9].name is a string.
Answer:
The new root will be 2.
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Explanation:
The binary tree is not properly presented (See attachment)
To answer this; first, we need to order the nodes of the tree in a pre-order traversal.
We use pre-order because the question says if something is removed from the left child.
So, the nodes in pre-order form is: 14, 2, 1, 5, 4, 16.
The root of the binary tree is 14 and if 14 is removed, the next is 2.
<em>Hence, the new root will be 2.</em>
Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
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