Answer:
Consider the following code.
Explanation:
save the following code in read_and_interp.m
function X = read_and_interp(s)
[m, n] = size(s);
X = zeros(m, 1);
for i = 1:m
if(str2num(s(i, 2:5)) == 9999)
% compute value based on previous and next entries in s array
% s(i, 2:5) retrieves columns 2-5 in ith row
X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;
else
X(i,1) = str2num(s(i,2:5));
end
end
end
======================
Now you can use teh function as shown below
s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];
read_and_interp(s)
output
ans =
96.000
114.000
109.500
105.000
112.000
Someone who wants to learn a skilled trade on the job should consider enrolling in class for the knowledge and skills.
Answer:
def insSort(arr):
ct=0;
for i in range(1, len(arr)):
key = arr[i]
j = i-1
while j >=0 and key < arr[j] :
arr[j+1] = arr[j]
j -= 1
ct=ct+1;
arr[j+1] = key
return arr,ct;
print(insSort([2,1]))
Output of the program is also attached.
AMPERE - a unit of measure for the flow of the current in a circut
Answer: c
Explanation:I done this before;DDD
