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dolphi86 [110]
3 years ago
7

A circle has its center at (1, 4) and a radius of 2 units. What is the equation of the circle? (1 point) (x + 2)2 + (y + 4)2 = 2

(x − 1)2 + (y − 4)2 = 4 (x + 1)2 + (y − 4)2 = 4 (x − 1)2 + (y − 4)2 = 2
Mathematics
2 answers:
Fed [463]3 years ago
8 0

Answer:

The answer is the second option

(x-1)^{2}+(y-4)^{2}= 4

Step-by-step explanation:

The general equation of a circle is:

(x-h)^{2}+(y-k)^{2}= r^{2}

in this equation (h,k) is the center of the circle and r is the radius, so if the center is in (1,4) and the radius is 2, the values of the constants are:

h = 1

k = 4

r = 2

And the formula for this circle is:

(x-1)^{2}+(y-4)^{2}= 2^{2}

(x-1)^{2}+(y-4)^{2}= 4

yawa3891 [41]3 years ago
5 0

Answer:

3rd one. The general form of a circle is set equal to the radius squared. So right side is 4 then plug in values until true.

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The -2 moves 2 to the right and the + 3 means 3 up.

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Step-by-step explanation:

1. To solve the system, set the equations equal to each other and solve for x.

2x - 5 = 2x + 7

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Read 2 more answers
For the point P (-17,25) and Q(-10,30), fins the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
Nonamiya [84]

Answer:

Distance = 8.6

M = (-13.5,27.5)

Step-by-step explanation:

Distance = \sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2

= \sqrt{(-10_ }- (-17)_{ })^2 + (30_{ }- 25_{ })^2

= \sqrt{(-10_{ }+ 17_{ })^2 + 5^2_

= \sqrt{7^2+5^2}

= \sqrt{49+25}

= \sqrt{74}

= 8.6

Midpoint = (\frac{x_{2}+x_{1}}{2};\frac{y_{2}+y_{1}}{2})

= (-10+(-17)) ÷ 2 ; (30+25) ÷ 2

= -27 ÷2 ; 55 ÷ 2

= -13.5, 27.5

3 0
3 years ago
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