Ask question

Ask question

All categories

3 years ago

6

Queen Zubaida wishes to choose a Satrap and a Vizier from among her $12$ courtiers. How many different ways can she assign the t

wo roles, assuming the same person cannot fulfill both roles?

1 answer:

meriva3 years ago

6 0

12 x 11 = 132

answer 132 ways

You might be interested in

Which statement is true? Select all that apply.

julsineya [31]

It’s b and c and i believe a

3 0

2 years ago

13/25 as a percentage

nadezda [96]

Hi , the answer is 52% , because 13 divided by 25 equals to 0.52 , we move the decimal two spaces to the right , so the answer is 52.

8 0

3 years ago

Read 2 more answers

297 x 65 two step problem dotted line

labwork [276]

Answer:

The answer is 19305

Step-by-step explanation:

5 0

2 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago

Nina can stitch 2/3 of dress in 4 hours. If represents the number of dresses and the represents the number of hours, which equat

Gelneren [198K]

Answer:

d :4h

Step-by-step explanation:

hope this helps (;

7 0

3 years ago

Read 2 more answers