Using google translate:
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?
Original: 10 by 6 cm ; Area = length * width = 10 x 6 = 60 cm²
first copy: enlarged to triple
10 x 3 = 30
6 x 3 = 18
30 x 18 = 540 cm²
second copy: halved
30 x 1/2 = 15
18 x 1/2 = 9
15 x 9 = 135 cm²
Two angles are said to be complementary, if the sum of the two angles is 90 degrees.
Given that the measure of angle SWT is 50 degrees, thus, the measure of the complementary angles will be 90 - 50 = 40 degrees.
From the diagram, the measure of angle USP is 40 degrees, hence it is a complement of angle SWT.
Recall that the angle on a straight line is equal to 180 degrees, thus the sum of the measures of angles USP, WST and TSV is 180 degrees.
i.e. mUSP + mWST + mTSV = 180 degrees
40 + 100 + mTSV = 180
mTSV = 180 - 140 = 40 degrees.
Hence angle TSV is complementary to angle SWT.
Therefore, the complementary angles to angle SWT are angle USP and angle TSV.
Answer : 84m^2=A
Photo Shows Solving Steps.
Hope this helps!
~ Penny
Answer:
y = (5/4)2^x
Step-by-step explanation:
The function value increases by a factor of 40/10 = 4 when x increases by 2. The function can be written as ...
y = (reference value)·(growth factor)^((x -reference)/(change in x for growth factor))
y = 10·4^((x-3)/2) . . . . . . using point (3, 10) as a reference
This can be simplified to ...
y = 10·2^(x -3) = 10/8·2^x
y = (5/4)2^x
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