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3 years ago

Solve this expression given below:

Mathematics

2 answers:

Reika [66]3 years ago

7 0

Answer:

2.9989054e+53

Step-by-step explanation:

seropon [69]3 years ago

6 0

B :)

if the bases are the same, and u are multiplying add the exponents.

So it will be 2^35 times 9^45

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Im really not sure with my answer, please tell which is the correct choice.

I am Lyosha [343]

Answer:

the orange one

Step-by-step explanation:

(10 + 10) : (5-3) =

20 : 2 =

5 0

2 years ago

If the sum of a number and 12 equals 32 what is the number

krek1111 [17]

20. 20+12=32. that's math(s).

8 0

3 years ago

4-member curling team is randomly chosen from 6 grade 11 students and 8 grade 12 students. What is the probability that the team

Ivanshal [37]

Answer:

0.5944 = 59.44% probability that the team has at least 2 grade 11 students

Step-by-step explanation:

The students are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

We have that:

6 + 8 = 14 students, which means that $N = 14$

6 grade 11 students means that $k = 6$

Teams of 4 members means that $n = 4$

What is the probability that the team has at least 2 grade 11 students?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,14,4,6) = \frac{C_{6,0}*C_{8,4}}{C_{14,4}} = 0.0699$

$P(X = 1) = h(1,14,4,6) = \frac{C_{6,1}*C_{8,3}}{C_{14,4}} = 0.3357$

Then

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0699 + 0.3357 = 0.4056$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4056 = 0.5944$

0.5944 = 59.44% probability that the team has at least 2 grade 11 students

5 0

3 years ago

If the perimeter of the rectangle is 30 cm and value of j is 8.

dezoksy [38]

2j +2h =30. That is the equation

2(8) + 2h = 30
16+ 2h =30

Subtract 16 from both sides
2h = 14
H=7

4 0

3 years ago

Write the letter for each expression in the box under the correct category in the table.

Ad libitum [116K]

Answer:

a) 9+(-3) + (-2) = 9 -5 = 4> 0 ⇒ Positive Sum

b) -12 +1 +11 = -12 +12 5 = 0 ⇒ Zero Sum

c) -3 +8 + (-4) = -7 + 8 -5 =-1 < 0 ⇒ Negative Sum

d) -4+9+(-10) = 9 -14 = -5 < 0 ⇒ Negative Sum

e) 3+(-2) + (-4) = 3 -6= -3 < 0 ⇒ Negative Sum

f) 2 + (-4) + 2 = 4 -4 = 0 ⇒ Zero Sum

Step-by-step explanation:

Positive Sum is defined as the condition in which the Sum of total of gains and losses is GREATER THAN ZERO.

Zero Sum is defined as the condition in which the Sum of total of gains and losses is EQUAL TO ZERO.

Negative Sum is defined as the condition in which the Sum of total of gains and losses is LESS THAN ZERO.

Now, here

a) 9+(-3) + (-2) = 9 -5 = 4> 0 ⇒ Positive Sum

b) -12 +1 +11 = -12 +12 5 = 0 ⇒ Zero Sum

c) -3 +8 + (-4) = -7 + 8 -5 =-1 < 0 ⇒ Negative Sum

d) -4+9+(-10) = 9 -14 = -5 < 0 ⇒ Negative Sum

e) 3+(-2) + (-4) = 3 -6= -3 < 0 ⇒ Negative Sum

f) 2 + (-4) + 2 = 4 -4 = 0 ⇒ Zero Sum

5 0

3 years ago