find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the la
rgest number
1 answer:
Answer:
10, 12, 14
Step-by-step explanation:
x, x+2, x+4
x+2(x+2)=x+4+20
3x+4=x+24
2x=20
x=10
x=10
x+2=12
x+4=14
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