Question

Can someone please do this substitution method question with the working out.

Answer 1

Answer:

Step-by-step explanation:

$T = \frac{1}{2}m^{2}+2m - 4\\\\T = 2m + 4\\\\\frac{1}{2}m^{2}+2m - 4 = 2m + 4\\\\\frac{1}{2}m^{2}+2m - 4 - 2m - 4 = 0$

Combine like terms

$\frac{1}{2}m^{2}+2m - 2m - 4 - 4 = 0\\\\\frac{1}{2}m^{2} - 8 = 0\\\\\frac{1}{2}m^{2} =8\\\\m^{2} = 8*2\\\\m^{2} = 16\\\\m = \sqrt{16}$

m = ± 4