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marusya05 [52]
3 years ago
13

Solve for x. Your answer must be simplified. 17r > -17

Mathematics
2 answers:
BartSMP [9]3 years ago
8 0

Answer: r>-1

Step-by-step explanation:

Given the inequality provided 17r > -17, you need to solve for "r".

To do this, you can divide both sides of the inequality by 17. Then you  get the following solution:

17r > -17\\\\\frac{17r}{17}>\frac{-17}{17}\\\\(1)r>(-1)\\\\r>-1

Now, you can expressed this solution in Interval notation form.

 Therefore, the solution of the inequality in Interval notation is:

(-1, \infty)

Snowcat [4.5K]3 years ago
4 0

Hello :D

Answer:

\boxed{R>-1}

The answer should have a negative sign.

Step-by-step explanation:

First, you do is divide by 17 from both sides of an equation.

\frac{17r}{17}>\frac{-17}{17}

Then, you simplify and solve to find the answer.

-17\div17=-1

\boxed{R>-1}, which is our answer.

I hope this helps you!

Have a great day! :D

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Step-by-step explanation:

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A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

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