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Mariulka [41]
3 years ago
5

Reuben has scored 70, 75, 83, and 80 on four Spanish quizzes. What score must he get on the next quiz to get an average of at le

ast 80?
Mathematics
2 answers:
butalik [34]3 years ago
6 0

Answer:

Step-by-step explanation:

MY D. I. C. K.

inna [77]3 years ago
6 0

Answer:

92

Step-by-step explanation:

Let x be the additional number.

Therefore Reuben score will be

70, 75, 83, 80 and x.

From the question, we were told that the next mark will make Reuben to have an average of 80. This can be illustrated below:

Mean = sum of marks / numbers of mark

Mean = 80

Number of mark = 5

80 = (70 + 75 + 83 + 80 + x) / 5

80 = (308 + x) / 5

Cross multiply

308 + x = 80 x 5

308 + x = 400

Collect like terms

x = 400 — 308

x = 92

Reuben must score at least 92

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Use the quadratic formula to solve the equation <br> 25x^2-30x+25=0
Reika [66]

Answer: x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

Step-by-step explanation:

25x^2-30x+25=0

x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}

\sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-2500}

=i\sqrt{2500-30^2}

=40i

x_{1,\:2}=\frac{-\left(-30\right)\pm \:40i}{2\cdot \:25}

x_1=\frac{-\left(-30\right)+40i}{2\cdot \:25},\:x_2=\frac{-\left(-30\right)-40i}{2\cdot \:25}

x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

8 0
3 years ago
Team B played three games and had an average of 13 hits in each game with 100 official at-bats. Three of the hits were home runs
Sophie [7]

.39

Pls mark brainliest!:)

5 0
3 years ago
How to do this?
Mandarinka [93]
This equation uses two properties of logarithms:

\ln(g^x) = x \ln(g)

\ln(a) + \ln(b) = \ln(ab)

So you could take the ln from left and right hand side in the equation, and get:

(2-x)ln 3 = x ln 5

then

2 ln 3 - x ln 3 - x ln 5 = 0 =>

x(ln 3 + ln 5) = 2 ln 3

so x = 2 ln 3 / (ln3 + ln5)

Now using the 1st property you can say 2 ln 3 is ln 3² = ln9
and using the 2nd property you can say ln3 + ln5 = ln15

so x= ln9 / ln15


7 0
3 years ago
David will spend at most $39 on gifts. So far, he has spent $22. What are the possible additional amounts he will spend? Use c f
iren2701 [21]

Answer:

c\leq \$17

Step-by-step explanation:

Let

c -----> the additional amount (in dollars) David will spend

we know that

The word " at most" in this context means "less than or equal to"

The amount David has spent plus possible additional amounts he will spend must be less than or equal to $39

so

The inequality that represent this situation is

22+c\leq 39

solve for c

subtract 22 both sides

c\leq 39-22

c\leq \$17

The maximum amount he could spend is $17

7 0
3 years ago
“Jessie has 2/3 of a bag of apples that she wants to divide equally among her 5 siblings. What fractional part of the bag
Nesterboy [21]

Answer:

2/15

Step-by-step explanation:

2/3*5

2/3*1/5=2/15

*=multipliy

6 0
3 years ago
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