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4 years ago

How would I solve k-17=(-12)

2 answers:

8 0

Ok your objective in this problem is to find out what k equals. To do that, you have to get "k" by itself. TO do that you have to add 17 on both sides. Making k equal 5

GrogVix [38]4 years ago

7 0

You would do -12 +17 which is 5

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*FIRST ANSWER GETS BRAINLIEST*

svet-max [94.6K]

The other solution to the equation is -3.

Step-by-step explanation:

Given equation is;

5x²+bx+12=0

One solution is -4/5

We will put this solution in Eqn to get the value of b first,

$5(\frac{-4}{5})^2+b(\frac{-4}{5})+12=0\\5(\frac{16}{25})+(\frac{-4b}{5})+12=0\\\frac{16}{5}-\frac{-4b}{5}=-12\\$

Multiplying each term by 5

$5*(\frac{16}{5})-\frac{-4b}{5}*5=-12*5\\16-4b=-60\\-4b=-60-16\\-4b=-76$

Dividing both sides by -4

$\frac{-4b}{-4}=\frac{-76}{-4}\\b=19$

Putting b=19 in given Eqn

5x²+19x+12=0

Here,

a=5 , b=19 , c=12

Using quadratic formula,

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\x=\frac{-(19)\±\sqrt{(19)^2-4(5)(12)}}{2(5)}\\\\x=\frac{-19\±\sqrt{361-240}}{10}\\\\x=\frac{-19\±11}{10}\\$

Either, or,

$x=\frac{-19+11}{10},\ \ \ \ \ \ x=\frac{-19-11}{10}\\x=\frac{-8}{10},\ \ \ \ \ \ \ \ \ x=\frac{-30}{10}\\x=\frac{-4}{5},\ \ \ \ \ \ \ \ \ \ x= -3$

The other solution to the equation is -3.

Keywords: linear equation, quadratic formula

Learn more about quadratic formula at:

#LearnwithBrainly

6 0

3 years ago

Random Problems. Help me please if u can.

Tems11 [23]

9) 4/50 = 0.08 = 8%

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3 years ago

Y = -5<br> 2x – 4y = 18<br> PLEASE HELP NO LINKS<br> LINKS=REPORT

Ber [7]

Answer:

x= -1

Step-by-step explanation:

since y is -5 then we would put that in the second equation:

2x - 4(-5) = 18

then it’s:

2x + 20 = 18

Then we subtract 20 from both sides

2x = -2

Last we divide both by 2 and we get x = -1

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MatroZZZ [7]

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sergij07 [2.7K]

Answer:

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