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storchak [24]
3 years ago
13

(Also pictured)

Mathematics
1 answer:
Romashka [77]3 years ago
3 0
Hello,

The slope of the 1st side is 2 (y=2x)
The slope of the 2 nd side is -1/2 (y=-x/2+5/2)
The two sides are perpendicular so we can find the  vertex.

y=2x (1)
2y+x=5
If we substitue y by is value in (1)
2(2x)+x=5==>5x=5
==>x=1 and y=2*1=2
Vertex is (1,2)
In order to find the rectangle we must know an other vertex.

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What is the linear function equation represented by the graph?
igor_vitrenko [27]

Look at the picture.

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (0, 1) and (2, 0). Substitute:

m=\dfrac{0-1}{2-0}=\dfrac{-1}{2}=-\dfrac{1}{2}\\\\y-1=-\dfrac{1}{2}(x-0)\\\\y-1=-\dfrac{1}{2}x\qquad|+1\\\\y=-\dfrac{1}{2}x+1

Answer: f(x)=-\dfrac{1}{2}x+1

5 0
3 years ago
Find the value of x in the triangle shown below. ​
iren2701 [21]

Answer:

x = 36°

Step-by-step explanation:

We know that the sum of all the interior angles in a triangle add up to 180°.

So in order to find the value of x, we have to:

x° + 97° + 47° = 180°

x° + 144° = 180°

x° = 180° - 144°

x° = 36°

3 0
3 years ago
Write 9 decimals with two decimal places that when rounded to the nearest tenth round to 8.7
Sindrei [870]
8.65
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5 0
4 years ago
Given f(x) = 6x^4 – 10x^3 + 40x – 50, find f(2)
ASHA 777 [7]
F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235
4 0
3 years ago
Pls help it’s due soon. thank you
Vikentia [17]
Area of triangle is
A=b•h/2
A=(10x+5)(2x-5)/2
A=20x^2-50x+10x-25/2
A=20x^2-40x-25/2
A=2(10x^2-20x-12.5)/2
cancel 2 in numerator and denominator
A=10x^2-20x-12.5 in^2
Hope this helps
5 0
3 years ago
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