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3 years ago

Given f(x) = 6x^4 – 10x^3 + 40x – 50, find f(2)

1 answer:

4 0

F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235

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Suppose that the store manager of a small rural pharmacy is doing a linear regression of daily sales of over-the-counter (OTC) d

Doss [256]

Answer:

3.83

Step-by-step explanation:

Mean of x = Σx / n

Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2

Sum of square (SS) :

(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8

Mean of y = Σy / n

Mean of y = (101 + 89 + 48 + 21 + 47) / 5 = 61.2

Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8

df = n - 2 = 5 - 2 = 3

Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6

√(Σ(y - ybar)² / df) = √1449.6 = 38.074

Standard Error = √(Σ(y - ybar)² / df) / √SS

Standard Error = 38.074 / √98.8

Standard Error = 3.83

4 0

3 years ago

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DedPeter [7]

Answer:

548.80

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

F(x)=3 over x+2-x-3 squared what is f(7)

dimaraw [331]

<u>Answer:</u>

$f(7)=\frac{-5}{3}$ or $f(7)=-1.67$

<u>Step-by-step explanation:</u>

We are given the following function of x and we are to find the value of $f ( 7 )$ :

$f ( x ) = \frac { 3 } { x + 2 } - \sqrt { x - 3 }$

Substituting the given value (7) in the above function to get:

$f(x)=\frac{3}{x+2}-\sqrt{x-3}$

$f ( 7 )= \ frac{3}{7+2}-\sqrt{7-3}$

$f(7) = \frac { 3 } { 9 } - \sqrt { 4 }$

$f(7)=\frac{1}{3}-2$

$f(7)=\frac{1}{3}-\frac{6}{3}$

$f(7)=\frac{-5}{3}$ or $f(7)=-1.67$

7 0

3 years ago

To put money into a savings account, CDs, and stocks is to___

-BARSIC- [3]

Answer:

I think its to invest.

Step-by-step explanation:

Knowledge, and past experience.

8 0

3 years ago

Which equation could be solved using this application of the quadratic formula? A. -2x2 â’ 8 = 10x â’ 3 B. 3x2 â’ 8x â’ 10 = 4 C

hodyreva [135]

The given question can be solve using quadratic formula.

The correct option is (c) $3x^2 +8x -10=-8$ .

Given:

The given equation is,

$x=\dfrac{-8\pm\sqrt{8^2-4(3)(-1)}} {2(3)}$ ---------------------------(1)

Write the general quadratic equation.

$ax^2 + bx +c=0$

Write the quadratic formula.

$x =\dfrac {-b \pm \sqrt{(b^2 - 4ac)} } {2a}$ ------------------------------- (2)

Compare equation (1) and (2).

$a=3\\b=8\\c=-2$

Substitute the value of $a$ , $b$ and $c$ in general quadratic.

$3x^2 +8x -2=0$

Subtract $8$ from each side of above equation.

$3x^2 +8x -2 -8=0-8\\3x^2 +8x -10=-8$

Thus, the correct option is (c) $3x^2 +8x -10=-8$ .

Learn more about quadratic equation here:

brainly.com/question/17177510

6 0

2 years ago