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mrs_skeptik [129]
3 years ago
9

A circuit consists of a series combination of 6.50-k\Omega and 5.00-k\Omega resistors connected across a 50.0-{\rm V} battery ha

ving negligible internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 5.00-k\Omega resistor using a voltmeter having an internal resistance of 10.0 \rm k \Omega.
What potential difference does the voltmeter measure across the 5.00-k\Omega resistor?

What is the true potential difference across this resistor when the meter is not present?
English
1 answer:
solniwko [45]3 years ago
5 0
The potential difference that the voltmeter measure across the 5.00-k/Omega resistor would be :
0.004 A
and The true potential difference across the resistor when the meter is not present is : 
21.74 V

Hope this helps
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