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4 years ago

Please help need an answer quick.

Mathematics

1 answer:

mel-nik [20]4 years ago

8 0

point A would be on -3, 7; point B would be on -9, 7; and point C would be on -6, 1.

Hope I helped.

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Is (6, 1) a solution to the inequality 11x + 3y > 4?

bezimeni [28]

Answer:

Yes (6,1) is a solution to the inequality

Step-by-step explanation:

Plug in the coordinate point and check:

11(6)+3(1)>4?

66+3>4?

69>4

Since 69 is indeed greater than 4, then (6,1) is a solution to the inequality.

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3 years ago

PLEASE HELP I NEED ASAP

Natasha2012 [34]

Answer:

Option A

Step-by-step explanation:

<u>Given inequality:</u>

x - 8 ≥ - 3

<u>Solve it:</u>

x ≥ 8 - 3
x ≥ 5

The graph includes the number line to the right of 5 and the 5 is included, so this point is represented by a full dot.

Correct choice is A

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3 years ago

Write an equation in point slope form for the line through the given point with the given slope (4,-6); m=3/5

77julia77 [94]

$The\ point-slope\ form:y-y_1=m(x-x_1)\\---------------------\\m=\frac{3}{5}\\\\(4;-6)\to x_1=4\ and\ y_1=-6\\\\subtitute:\\\\y-(-6)=\frac{3}{5}(x-4)\\\\\boxed{y+6=\frac{3}{5}(x-4)}$

4 0

3 years ago

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Compare the decimals 564.278 and 564.3.

irga5000 [103]

The answer is c less than

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4 years ago

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What is the binomial expansion of (x + 2y)7?

borishaifa [10]

<h2>Thus, the required "option 4)" is correct.</h2>

Step-by-step explanation:

We find,

$(x+2y)^7$

To find, the binomial expansion of of $(x+2y)^7$ = ?

We know that,

$(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n$

∴ $(x+2y)^7$

Here, n = 7, x = x and y = 2y

$(x+2y)^7$ = $^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7$ $=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7$

$=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7$

∴ The binomial expansion of of $(x+2y)^7$

$=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7$

Thus, the required "option 4)" is correct.

7 0

3 years ago