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const2013 [10]
3 years ago
13

7 = x + 12 A. -19 B. -5 C. 4 D. 5

Mathematics
2 answers:
Oduvanchick [21]3 years ago
6 0

x+12=7

x+12-12=7-12

x=-5

Elena L [17]3 years ago
5 0

You have to get "X" by itself so you subtract 12, 7-12 is -5 so "X" = - 5


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A student can type 2/3 of a page in 1/5 hour. how many pages can the student type in an hour.
professor190 [17]

Here is your answer

3 \frac{1}{3} pages

REASON:

[CONCEPT USED: <u>Unitary method</u>]

Number of pages typed by student in 1/5 hour = 2/3

No. of pages typed by the student in 1 hour= \frac{2/3}{1/5}

= \frac{2}{3}×5

= 10/3

=

3\frac{1}{3}

So number of pages written in 1 hour are

3 pages and 1/3 of a page

HOPE IT IS USEFUL

8 0
3 years ago
Simplify by using the law of indices:<br>y^a(b+c)×y^b(c-a)×y^c(a-b)​
tia_tia [17]

Answer:

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Step-by-step explanation:

Using the law if indices

a^{m} × a^{n} = a^{(m+n)}

Thus to simplify the expression add the 3 exponents

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= 2ac

Then the expression simplifies to

y^{2ac}

4 0
3 years ago
The steps for adding mixed numbers with unlike denominators are very ____________
raketka [301]

Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:thanks daddy

5 0
2 years ago
A sample of 20 pages was taken from a Yellow Pages directory. On each page, the mean area devoted to display ads was measured in
Snezhnost [94]

The 95 percent confidence interval for the mean is (266.76,426.24).

A confidence interval is how much uncertainty there is with any particular statistic. Confidence intervals are often used with a margin of error. It tells you how confident you can be that the results from a poll or survey reflect what you would expect to find if it were possible to survey the entire population. Confidence intervals are intrinsically connected to confidence levels.

The formula of Confidence Interval =  Mean ±   t\frac{Standard Deviation}{\sqrt{number of observations} }

where t is a constant

Given:

Mean = 346.5

Standard Deviation = 170.378

t-critical value for 95% Confidence interval with degrees of freedom(df)=n-1= 19 is 2.093

∴ Substituting values in formula we get

E = 2.093 X170.378/\sqrt{20} = 2.0931.96 x 38.0976=79.74

95% Confidence interval : (346.5-79.74,346.5+79.74)

95% Confidence interval : (266.76,426.24)

Learn more about confidence intervals here :

brainly.com/question/24131141

#SPJ4

4 0
2 years ago
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