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joja [24]
3 years ago
11

If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i

ntegers?
Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

First Integer = n = 45

Second Integer = n+1 = 45 + 1 = 46

And Third Integer = n+ 2 = 45 +2 = 47

Step-by-step explanation:

Let First integer = n

Second Integer = n+1

Third Integer = n+2

According to the question given (If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third) the equation will be:

138 - n = (n+1) + (n+2)

Solving the equation:

138 - n = n+1+n+2

138 - n = 2n+3

138 - 3 =2n +n

135 = 3n

135/3 = n

=> n= 45

So, First Integer = n = 45

Second Integer = n+1 = 45 + 1 = 46

And Third Integer = n+ 2 = 45 +2 = 47

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3 years ago
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9 0
3 years ago
Read 2 more answers
Point G is between F and H. FH= 102, FG=5x+9, and HG=9x-5
dexar [7]

a)

FH = 102, FG = 5x + 9. HG = 9x - 5     <em>Given</em>

  FG    +   HG   =    FH                        <em>Segment addition postulate</em>

5x + 9 + 9x - 5 =  102                         <em>Substitution</em>

            14x + 4 = 102                        <em>Simplify (added like terms)</em>

                  14x = 98                          <em>Subtraction property of equality</em>

                     x = 7                             <em>Division property of equality</em>

b)   FG = 5x + 9  = 5(7) + 9   = 35 + 9   = 44

c)   HG = 9x - 5   = 9(7) - 5   = 63 - 5   = 58

Answers: a = 7, b = 44, c = 58

7 0
3 years ago
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