3, 1, -1, -3, -5
-2 -2 -2 -2
a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
a₁₄ = -2(14) + 5
a₁₄ = -28 + 5
a₁₄ = -23
The answer is C.
The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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F(x) = -x² + 4
f(3) = -3² + 4
f(3) = -9 +4
f(3) = -5
Answer:
667.38
Step-by-step explanation:
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