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Alenkinab [10]
3 years ago
12

A. Kalisha made two dozen large buns. She ate 1/2 of a bun and gave her mother and father one each. How many buns does she have

left?
b. She is going to cut the remaining buns into thirds for a party. How many 1/3 -size buns will she have?

First one is brainliest Answer!!!!
Mathematics
1 answer:
REY [17]3 years ago
8 0
A. Well she starts with 24 buns. She ate 1/2 half of a bun leaving 23 1/2 buns left. Then she gave her mother and father a bun each so you do 23 1/2 - 2 which gets you 21 1/2 buns. So the total number of buns that she has left is 21 and 1/2 buns.
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Lisa is mailing a letter to a friend. Postage costs $0.32 for the first ounce and $0.23 for the additional ounce. How heavy can
Advocard [28]

Answer: 8.3 ounces

Step-by-step explanation:

simple, there's a flat fee for 1 ounce, then 23 cents for each ounce following.

so $2 - $0.32 = $1.68

1.67 / 0.23 = 7.3 ounces

7.3 ounces + 1 ounces (from the flat fee we subtracted)

which equals 8.3

7 0
2 years ago
Faron wants to paint the four walls in his bedroom. The room measures 12 ft long, 10 ft wide and 8 ft high. There are two doors
Rainbow [258]

Answer:

319 square feet.

Step-by-step explanation:

The walls of the room (the ones on the long side) have an area of 12 x 8 = 96 square feet each one. Thus, their area is 96 x 2= 192 square feet.

The other two walls have an area of 10 x 8 = 80 square feet each one. Thus, their area combined is 80 x 2 = 160 square feet.

Therefore, we have that the total area of the four walls is

192 +160 = 352 square feet

However, we have a door and a window that won't be painted.

The area of the door is: 3 x 7 =21 square feet

The area of the window is 3 x 4 = 12 square feet

Thus, the total amount of area that won't be painted is

21 + 12 = 33 square feet.

So we are going to take the total area minus the area that won't be painted to know the total area that Faron will pain:

352 - 33 = 319 square feet.

Thus, she will paint 319 square feet

4 0
3 years ago
A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variabl
Zigmanuir [339]

Answer:

E(w) = 1600000

v(w) = 240000

Step-by-step explanation:

given data

sequence = 1 million iid  (+1 and +2)

probability of transmitting a +1 =  0.4

solution

sequence will be here as

P{Xi = k } = 0.4              for k = +1

                  0.6              for k = +2

and define is

x1  + x2 + ................ + X1000000

so for expected value for W

E(w) = E( x1  + x2 + ................ +  X1000000 )   ......................1

as per the linear probability of expectation

E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)

E(w) = 1600000

and

for variance of W

v(w) = V ( x1  + x2 + ................ + X1000000 )    ..........................2

v(w) = V x1  + V x2 + ................  + V  X1000000

here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j

so

v(w) = 1000000 ( v(x) )

v(w) = 1000000 ( 0.24)

v(w) = 240000

8 0
2 years ago
Passes through ( 4, 2), parallel to y = x + 5
Hoochie [10]

Answer:

y = x - 2

Step-by-step explanation:

You can subtract 4 from the x and y to get where the y-intercept would be.

8 0
3 years ago
Read 2 more answers
2. A two-stage rocket is in development. The required probability is for the overall rocket to be a minimum of 97% reliable for
ikadub [295]

Answer: The minimum reliability for the second stage be 0.979.

Step-by-step explanation:

Since we have given that

Probability for the overall rocket reliable for a successful mission = 97%

Probability for the first stage = 99%

We need to find the minimum reliability for the second stage :

So, it becomes:

P(overall reliability) = P(first stage ) × P(second stage)

0.97=0.99\times x\\\\\dfrac{0.97}{0.99}=x\\\\0.979=x

Hence, the minimum reliability for the second stage be 0.979.

4 0
3 years ago
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