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aivan3 [116]
3 years ago
15

Please really need help on this thanks

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
5 0
5X-20=4X+7

5X-4x=20+7

X=27°
bogdanovich [222]3 years ago
3 0
X= 27!! Yesssssssssss
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Y=-155. Put in a table of 3 rows.
Alja [10]

Answer:

51.6666666667

Step-by-step explanation:

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WILL GIVE BRAINLIEST<br><br>(3x – 14) (2x + 10) <br><br>Find the value of x.​
Brut [27]

Answer:

(3x - 14) = (2x+ 10) { Because the angles are vertically opposite to each other}

3x-2x= 14+10

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Graph the system of equations on your graph paper to answer the question. {y=−x+3
makkiz [27]
The answer is (x, y) = (-1, 4) hope this helped

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3 years ago
The point B(1, 1) is rotated 90° counterclockwise around the origin. What are the co
Thepotemich [5.8K]

Given that the point B is (1,1) is rotate 90° counterclockwise around the origin.

We need to determine the coordinates of the resulting point B'.

<u>Coordinates of the point B':</u>

The general rule to rotate the point 90° counterclockwise around the origin is given by

(x, y) \rightarrow(-y, x)

The new coordinate can be determined by interchanging the coordinates of x and y and changing the sign of y.

Now, we shall determine the coordinates of the point B' by substituting (1,1) in the general rule.

Thus, we have;

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3 0
3 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
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