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3 years ago

Write an expression for the model. Find the sum.

Mathematics

1 answer:

AVprozaik [17]3 years ago

3 0

The first choice. -3 is the party to the left of the vertical all line. 2 is the part to the right. that segment is 5 units long

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A. -4m - 12 - 5m = 13

vladimir2022 [97]

Answer:

Hope this helps!

Step-by-step explanation:

6 0

3 years ago

A geologist noticed that a land along a fault line moved 24.8 centimeters over the past 175 years . On average, how much did the

olasank [31]

Answer:

On average, the land moved 0,14 cm each year.

Step-by-step explanation:

To know how much did, on average, the land move, we should divide the total number of cm over the total number of years:

x=24.8 cm/175 years

x=0,1417 cm each year

If we divide years over cm we will get x in years each cm, which is wrong.

Because the problem asks for the answer rounded to the hundredths place:

x= 0,14 cm each year

8 0

3 years ago

What is the correct line graph for y=3x+5?

AysviL [449]

Answer:

The equation y=−3x+5 is in slope intercept form, and represents a straight line in which -3 is the slope, and 5 is the y -intercept.

3 0

3 years ago

Pls help! evaluate the function for x=3a.

Musya8 [376]

The answer is choice C .

5 0

3 years ago

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among

jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\\=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0

4 years ago