Write an expression for the model. Find the sum.

Mathematics

1 answer:

AVprozaik [17]3 years ago

3 0

The first choice. -3 is the party to the left of the vertical all line. 2 is the part to the right. that segment is 5 units long

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What is .64 divided by 3.456

Simora [160]

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3 years ago

Write the quadratic function in vertex form. Then identify the vertex.

ddd [48]

Answer:

Step-by-step explanation:

To put the equation into vertex form, we need to complete the square

$g(x) = (x^2 - 4x + ...) - 1\\g(x) = (x^2-4x+(\frac{4}{2})^2 ) - 1 - (\frac{4}{2})^2 \\g(x) = (x-2)^2 - 5\\$

This is in the form

$y = a(x-h)^2 + k\\(h, k)$

So, the vertex is (2, -5)

and $g(x) = (x-2)^2-5$

7 0

3 years ago

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$