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Naily [24]
3 years ago
11

Find the volume of a cube where the length of each side is 6 centimeters.

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

hope it will help u..........

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Factorise: x³ + 32x + 20.​
LenKa [72]

Answer:

cant be factored

Step-by-step explanation:

7 0
3 years ago
At the movie theater all snacks and all movie tickets are priced the same. Four snacks and three movie tickets cost $40. Two sna
Nataliya [291]

We know that four snacks and three movie tickets cost $40 dollars, and when you take away 2 snacks but still keep the tickets, its $32.

2 snacks= $8

What i did to find the cost of each ticket is I divided 8 by 2 (8/2) and ended getting $4

1 snack= $4

Now to find the cost of each ticket, i divided 2 snacks ($8) and got this equation:

32 - 8= 24

3 tickets= $24

Now to find the amount for each ticket, i divided 24 by 3 (24/3) and got the answer:

1 ticket= $8

Therefore, snacks are $4 and movie tickets are $8

x tickets= 8x

x snacks= 4x

<em>Thank you! Btw can i please get brainly :3</em>

7 0
3 years ago
If csc x = −5, find csc(−x) find the period and horizontal shift
ella [17]

Answer:

\csc (-x) = - \csc x = - ( - 5) = 5

Period is 2π

Horizontal shift = 0

Step-by-step explanation:

We know that \sin (-x) = - \sin x and as \csc x = \frac{1}{\sin x}, so, we can write \csc (-x) = - \csc x

Therefore, the if \csc x = - 5 then \csc (-x) = - \csc x = - ( - 5) = 5 (Answer)

Now, the period of \csc x is 2π, hence the period of \csc (- x) is also 2π.  (Answer)

Again. \csc ( - x) = \csc (-x + 0), hence, the horizontal shift of \csc (- x) is 0. (Answer)

6 0
3 years ago
PLZZZZZZZ NEED HELP!!!!!!
Maurinko [17]
I think it is $30 since it has the highest probability.
7 0
3 years ago
Don’t understand!! please help!! and show work!
goldenfox [79]

To find the correct answer, you have to simplify the equation.

Multiply -1/2 by everything in the parenthesis.

3/4x - 3x - 1/2 - 3x. Combine like terms.

-21/4x - 1/2. Turn -21/4x into a mixed number.

-5 1/4x - 1/2.

Your answer is D

3 0
3 years ago
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