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Over [174]
4 years ago
9

4/9(y+3)=g solve for y

Mathematics
1 answer:
Kipish [7]4 years ago
4 0

4(y+3)=9g

4y+12=9g

4y=9g-12

y=(9g)/4-3

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1/2r -3= 3 (4-3/2r) solve for r
s2008m [1.1K]

1/2r -3= 3 (4-3/2r) is to be solved for r.


I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.


Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .

Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:


r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r


Now expand the right side, using the distributive property of

r - 3 = 24 - 9r


Regrouping so as to combine like terms:


10r = 30


Solving for r: r = 30/10 = 3


The value of r that satisfies this equation is 3

8 0
3 years ago
"what predicted value" of y "will have the smallest" mean squared error
Alenkasestr [34]
The smallest value squared would be sqrt0 or 0.  Please mark Brainliest!!!
4 0
3 years ago
If A(0, 0) and B(2, 5), find AB. If necessary, submit your answer as a decimal to the nearest tenth. (Remember: AB means "the di
Olin [163]
To determine the distance between two points, we use the equation,
                                   distance = √(x₂ - x₁)² + (y₂ - y₁)²
Substituting the known values for the abscissa and ordinates of the points,
                                distance = √(0 - 2)² + (0 - 5)² = √29 ≈ 5.39 
Therefore, the distance between these two points is approximately equal to 5.39. 
8 0
4 years ago
ASAP PLZ WILL GIVE BRAINLIEAT AND SHOUTOUT!
Vadim26 [7]
Hi there!

The formula for the perimeter of a rectangle is P = 2 (l + w).

We can simplify this formula so that we can find the solutions easier.
P = 40

40 = 2 (l + w)
divide both sides by 2

40/2 = l + w
20 = l + w

So the length + width has to equal to 20.

So your answers would be B , C , D.
Hope this helped! :)
6 0
3 years ago
50 pts help pls...
Masteriza [31]
Felix and Tyler means
Mean = (9.4+54)/2= 31,7
Median= (7+66)/2= 36,5

Is this what you are looking for??
5 0
3 years ago
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