Look at the picture please

A farmer had large herd of goats. Besides the 4 goats that slept in his bed, he had 7 barns full of goats. How many goats were i

fiasKO [112]

95-4=91 then 91 divided 7=13 (95-4) divided 7=13

6 0

3 years ago

A manufacturer of a new medication on the market for Alzheimer's disease makes a claim that the medication is effective in 65% o

NeX [460]

Answer:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

Step-by-step explanation:

Data given and notation

n=180 represent the random sample taken

X=115 represent the adults with the medication was effective

$\hat p=\frac{115}{180}=0.639$ estimated proportion of adults with the medication was effective

$p_o=0.65$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is less than 0.65.:

Null hypothesis: $p \geq 0.65$

Alternative hypothesis: $p < 0.65$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

3 0

3 years ago

Combine like terms - 7 -3(4-2x)-10x

Shtirlitz [24]

Answer:

The simplified form would ve -19 - 4x

Step-by-step explanation:

Before we combine anything, we first must expand the expression by distributing the -3 to the terms in the parenthesis.

-7 - 3(4 - 2x) - 10x

-7 - 12 + 6x - 10x

Now we can combine the terms with and without variables.

-19 - 4x

8 0

3 years ago

Read 2 more answers

Find 3/7⋅9/10 . Write your answer as a fraction in simplest form.

aev [14]

27/70 is the fraction

8 0

3 years ago

Read 2 more answers

Give the degree of the polynomial <br> -3w+x^6y^5-2+5y^4w^3x^2

Jlenok [28]

Answer:

Here the degree of the polynomial is 11.

Step-by-step explanation:

To find the degree of the multivariate polynomials, we need to add up the powers of all the variables. So the total degree is given by the sum of all the powers of the highest powers terms.

Now in the given polynomial $-3w+x^6y^5-2+5y^4w^3x^2$

the term with the highest total powers is $x^6y^5$ and thus the total power is 6+5=11.

And hence the degree of this polynomial is 11.

5 0

3 years ago