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3 years ago

A(n) __________ is a recording of a motion picture, or television program for playing through a television.

Computers and Technology

2 answers:

Mamont248 [21]3 years ago

7 0

The answer is C: Video.

A video is anything that is considered to be recorded, broadcasted, or a display of moving visual images. Most videos must be visual. A video transmits a signal to a screen and might vary depending on a number of factors such as the aspect ratio, display resolution, color capabilities, and refresh rate among others. Things like TV shows, music videos, movies, and video games are always considered videos.

lisabon 2012 [21]3 years ago

3 0

A video is a recording of a motion, or television program for playing through a television. A camcorder is a device or gadget that is used to record a video. audio is the sounds that we hear and mix media is a tool used to edit the video.

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Answer: it is the code it is wrong

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2 years ago

In this problem. we consider the delay introduced by the tcp slow-start phase. consider a client and a web server directly conne

Tatiana [17]

The time that is required to retrieve the object (including TCP connection establishment) when $4S/R > S/R > RTT > 2S/R$ is equal to $\frac{14S}{R}+4RTT$

<h3>How to calculate the time needed to receive all objects.</h3>

In this scenario, we would denote the round-trip time that exist between the web server and the client with $RTT$ and assume that it is constant.

The time that is required to retrieve the object when $4S/R > S/R > RTT > 2S/R$ would be calculated by adding the round trip of sender and reciever together as follows:

Round trip = RTT + RTT

Next, we would determine the delay in packet transmission:

<u>Note:</u> $\frac{8S}{R}+\frac{4S}{R}=\frac{12S}{R}$

$Time = (\frac{S}{R} +RTT)+(\frac{S}{R} +RTT)+(\frac{12S}{R}) +RTT+RTT\\\\Time = \frac{14S}{R}+4RTT$

When $S/R +RTT > 4S/R$ , we have:

The time that is required to retrieve the object would be calculated by adding the round trip of sender and reciever together as follows:

$Time = (\frac{S}{R} +RTT)+(\frac{S}{R} +RTT)+(\frac{8S}{R}) +RTT+RTT\\\\Time = \frac{11S}{R}+5RTT$

The time that is required to retrieve the object when $S/R > RTT$ would be calculated by adding the round trip of sender and reciever together as follows:

$Time = (\frac{S}{R} +RTT)+(\frac{14S}{R}) +RTT\\\\Time = \frac{15S}{R}+3RTT$

Read more on round trip here: brainly.com/question/6884622

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kakasveta [241]

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3 years ago

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3 years ago

Read 2 more answers

A hacker gains access to a web server and reads the credit card numbers stored on that server. Which security principle is viola

wel

Answer:

Confidentiality

Explanation:

Cyber security can be defined as a preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.

In Cybersecurity, there are certain security standards, frameworks, antivirus utility, and best practices that must be adopted to ensure there's a formidable wall to prevent data corruption by malwares or viruses, protect data and any unauthorized access or usage of the system network.

In this scenario, a hacker gains access to a web server and reads the credit card numbers stored on that server. Thus, the security principle which is violated is confidentiality.

Confidentiality refers to the act of sharing an information that is expected to be kept secret, especially between the parties involved. Thus, a confidential information is a secret information that mustn't be shared with the general public.

This ultimately implies that, confidentiality requires that access to collected data be limited only to authorized staffs or persons.

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3 years ago