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harkovskaia [24]
3 years ago
10

6. All angles in the figure below are right angles. What is the area of the figure? (4 point)

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

Area the figure = 45 - 9 = 36 units² ⇒ last answer

Step-by-step explanation:

<em>"I have added screenshot of the complete question as well as the diagram"</em>

All the angles of the figure are right angles

<u>From the attached figure:</u> <em>we can find the area of the figure by subtracting the area of the cutting part from the area of the rectangle of dimensions 9 units and 5 units</em>

∵ All the angles of the figure are right angles

∴ We can consider that the figure of dimensions 9 units and 5 units

  as a rectangle

∵ Area of any rectangle A = L × H , where L, H are the dimensions

  of the rectangle

∵ L = 9 units and H = 5 units

∴ Area of the rectangle = 9 × 5 = 45 units²

- The dimensions of the cutting part are 3 units and

  [9 - (2 + 4) = 9 - 6 = 3 units]

∴ The cutting part is a square

∵ Area any square = S², where S is the length of the side of the square

∵ S = 3 units

∴ The area of the cutting part = 3² = 9 units²

∵ Area of the figure = area rectangle - area square

∵ Area the rectangle = 45 units²

∴ Area the square = 9 unit²

∴ Area the figure = 45 - 9 = 36 units²

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On a map the perimeter of the is 0.251 meters. The actual perimeters of the park is 1,000 times as large. What is the actual per
raketka [301]

The actual perimeter of the park is \boxed{\bf251{\text{ meters}}}.

Further explanation:

Given:

The perimeter of the park is on a map 0.251{\text{ meters}}. The measured perimeter of the park is 1000 times as large.  

Calculation:

The distance of the closed figure is called as the perimeter.

The perimeter of the attached Figure 1 can be calculated as,

\begin{aligned}{\text{Perimeter}}&=a+a+b+b\\&=2\left({a+b}\right)\\\end{aligned}

Here, x,y{\text{ and }}z is the length of the shape.

From place value chart, 10 tens is equal to 1 hundreds.

Tenths are one place after the decimal and hundredths are two places after the decimal.

Two tenths can be written in the form of decimal as follows:

\dfrac{2}{{10}}=0.2

Five hundredths can be written in the form of decimal as follows:

\dfrac{5}{{100}}=0.05

One thousandths can be written in the form of decimal as follows:

\dfrac{1}{{1000}}=0.001

Therefore, the number 0.251 can be written as,

\begin{aligned}0.251&=\frac{2}{{10}}+\frac{5}{{100}}+\frac{1}{{1000}}\\&=0.2+0.05+0.001\\&=0.251\\\end{aligned}

On the map the perimeter of the park is 0.251{\text{ meters}}.

Let {\text{P}} be the actual perimeter of the park.

The actual perimeter of the park can be calculated as follows,

\begin{aligned}{\text{P}}&=0.251\times1000\\&=251{\text{ meters}}\\\end{aligned}

Thus, the actual perimeter of the park is \boxed{\bf251{\text{ meters}}}.

Learn more:

1. Learn more about problem on function brainly.com/question/1632445

2. Learn more about problem on triangle brainly.com/question/7437053

3. Learn more about problem on range and domain of functions brainly.com/question/3412497

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Numbers

Keywords: Perimeter, park, map,  , measured, 1000 times large, distance, closed figure, length, shape, place value chart, hundreds, tenths.

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