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Dovator [93]
3 years ago
6

A plane is going to fly 300 miles at a planned speed of 530 mph. The flight will have an average headwind of w miles per hour th

e entire time, meaning the plane is flying directly against the wind. The time
Tin hours of the flight is a function of the speed of the headwind w, in mph, and can be modeled by
300
T(W) =
530-W
At what value of w does the graph have a vertical asymptote ? Explain what this asymptote means in this situation.
Mathematics
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

Step-by-step explanation:

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Answer: a - 4

b - 1

c - 2

d - 3

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Step-by-step explanation:

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An inventory record for the bookstore of a local college shows a receipt of 150 accounting books on May 1. Another shipment of 2
babunello [35]
Hi there
Let's order the transactions
on May 1. 150
less On May 20 100 books were sold

Less June 3, 31 books were purchased by the students

Add on June 15 25 books arrived

Add On June 17, a shipment of 150 books arrived

So
the number on hand on June 17
150−100−31+25+150
=194....answer

Hope it helps
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3 years ago
Help, I'm doing rhis problem and need help checking if I'm right.
umka2103 [35]
To me it looks like your right
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3 years ago
Assured normally costs £42 if you receive a 15% discount how much change will you get from £50
vesna_86 [32]
5% of £42 = £2.10
10% of £42 = £4.20
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£42 - £6.30 = £35.70

£50 - £35.70 = £14.30

the answer is £14.30

6 0
3 years ago
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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
2 years ago
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