Sophia was asked to find the original dimension of a reduced hexagon. Sophia found that the enlarged hexagon's dimensions were j
2 answers:
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Here is what I did....
Thinking about the graph of f(x), the rate of change is zero whenever there is an extremum.
First, differentiate f(x)
Next, find the zeros of f'(x) by factoring.
Now, we substitute these x-values into the original equation to find the coordinates.
(-2.667, 11.481), (0, 2)
First, differentiate f(x)
Next, find the zeros of f'(x) by factoring.
Now, we substitute these x-values into the original equation to find the coordinates.
(-2.667, 11.481), (0, 2)
Answer:
Step-by-step explanation:
General equation of ellipse :
Given: Vertices of ellipse : (± 9,0)
Since the vertices are of the form (± a, 0).
i.e. a=9
Thus, the major axis is along x-axis.
Also, foci of the ellipse = (±5,0)
Since, foci is of the form (± c,0), i.e. c=5
Since
Equation of ellipse :
Hence, the required equation :