We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
Answer:
5600 feet
Step-by-step explanation:
If it is dropping 1400 every minute then to find the elevation at 4 minutes, you have to multiply 1400 with 4.
Answer:
x = 10°
Step-by-step explanation:
a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"
Therefore, in cyclic quadrilateral ABDE,
m∠ABD + m∠AED = 180°
110° + m∠AED = 180°
m∠AED = 180° - 110°
= 70°
b). AD = ED [Given]
m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]
m∠EAD = m∠AED = 70°
By triangle sum theorem in ΔABD,
m∠BAD + m∠ABD + m∠ADB = 180°
m∠BAD + 110° + 40° = 180°
m∠BAD = 180 - 150
= 30°
m∠AEB = m∠AED + m∠DAB [By angles addition postulate]
m∠AEB = 70° + 30°
= 100°
By triangle sum theorem in the large triangle,
x° + m∠AEB + m∠EAB = 180°
x° + 100° + 70° = 180°
x = 180 - 170
x = 10°
Answer:
∠2 = 55°
Step-by-step explanation:
Given that the triangle has 2 congruent sides then the triangle is isosceles.
Thus the 2 base angle are congruent, both equal to ∠2
The sum of the 3 angles in a triangle = 180
7x + 6 + 7x + 6 + 70 = 180, that is
14x + 82 = 180 ( subtract 82 from both sides )
14x = 98 ( divide both sides by 14 )
x = 7
Hence
∠2 = 7x + 6 = (7 × 7) + 6 = 49 + 6 = 55°
Answer:
1. (-7, 5 ) and (-1, 3)
(3-5)/(-1+7)= -2/6 = -1/3
y - 5 = (-1/3)(x + 7)
y - 5 = (-1/3)x - 7/3
y - 15/3= (-1/3)x - 7/3
y = (-1/3)x + 8/3
2. (-1-3)/(3-0)= -4/3
y + 3 = (-4/3)(x + 1)
y + 3 = (-4/3)x - 4/3
y + 9/3 = (-4/3)x - 4/3
y = (-4/3)x + 5/3
the answer is neither