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babunello [35]
2 years ago
6

While he was at the grocery​ store, Raymond purchased a box of candy for himself. On the way back to the​ dorm, he ate 1/2 of th

e candy. As he was putting away the​ groceries, he ate 1/3 of what was left. There are now 2 chocolates left in the box. How many chocolates were in the box to begin​ with?
Mathematics
2 answers:
viva [34]2 years ago
7 0

Answer:

6 chocolates

Step-by-step explanation:

If there was 2 chocolates left and he had just eaten a third that would mean he had eaten 1

That would mean there would have been three chocolates before he put away the groceries

Double that to make up for the chocolates eaten during the walk home = 6

madreJ [45]2 years ago
4 0
6 chocolate

the hint is he ate 1/3
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Compute and compare the side lengths of the two figures. Does this support an argument claiming that they are congruent? What el
Sunny_sXe [5.5K]
We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].

AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13

BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13

CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13

DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13

The two polygons are squares with the same side lengths. 

But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions: 
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.

The third condition was not proven.
6 0
3 years ago
Read 2 more answers
4. An airplane descends at a rate of 1,400 feet per minute. Once the airplane starts its descent, what will be its change in ele
Evgesh-ka [11]

Answer:

5600 feet

Step-by-step explanation:

If it is dropping 1400 every minute then to find the elevation at 4 minutes, you have to multiply 1400 with 4.

5 0
2 years ago
Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
2 years ago
23) m 2 = 7x + 6<br>70°​
lakkis [162]

Answer:

∠2 = 55°

Step-by-step explanation:

Given that the triangle has 2 congruent sides then the triangle is isosceles.

Thus the 2 base angle are congruent, both equal to ∠2

The sum of the 3 angles in a triangle = 180

7x + 6 + 7x + 6 + 70 = 180, that is

14x + 82 = 180 ( subtract 82 from both sides )

14x = 98 ( divide both sides by 14 )

x = 7

Hence

∠2 = 7x + 6 = (7 × 7) + 6 = 49 + 6 = 55°

3 0
3 years ago
One line passes through the points (-7,5)
Studentka2010 [4]

Answer:

1. (-7, 5 ) and (-1, 3)

(3-5)/(-1+7)= -2/6 = -1/3

y - 5 = (-1/3)(x + 7)

y - 5 = (-1/3)x - 7/3

y - 15/3= (-1/3)x - 7/3

y = (-1/3)x + 8/3

2. (-1-3)/(3-0)= -4/3

y + 3 = (-4/3)(x + 1)

y + 3 = (-4/3)x - 4/3

y + 9/3 = (-4/3)x - 4/3

y = (-4/3)x + 5/3

the answer is neither

7 0
3 years ago
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