(x^2 + 3)(5x + 9)
5x^3 + 9x^2 + 15x + 27
<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
Answer: jackson is 12
explanation:
let the age be represented by x
jackson is 2 times older than shelly so
2x is jackson’s age and x is shelly’s age
since the sum of their ages is 18 then:
2x + x = 18
solve:
3x = 18 ➔ divide by 3 on both sides
x = 6
so now we know shelly is 6
jackson is 2 times older than her so:
2(6) = 12
Line graphs can be used to compare changes over the same period of time for more than one group. Pie charts are best to use when you are trying to compare parts of a whole. They do not show changes over time.
Answer:
Let ten's place digit =x and unit place digit =y
Number=10x+y
x+y=5 ...(i)
10x+y−9=10y+x
9x−9y=9x−y=1 ...(ii)
from (i) and (ii) we get,
x=3,y=2
∴Number=10×3+2=32.
Step-by-step explanation:
Hope it helps!
